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emmainna [20.7K]
3 years ago
13

1) A plane's velocity increases from 40 m/s to 100 m/s over a 10 second interval. What is the plane's average acceleration for t

his interval? *
​
Physics
1 answer:
Yakvenalex [24]3 years ago
8 0

Answer:

average acceleration = 6 \frac{m}{s^2}

Explanation:

Recall that the average acceleration (a)  is defined by the change in velocity from an initial velocity (v_i), to a final velocity (v_f) over the time (t) it took that change to happen. Then, in mathematical terms this is:

a=\frac{v_f-v_i}{t}

with our information this becomes:

a=\frac{v_f-v_i}{t} = \frac{100-40}{10}=6\,\frac{m}{s^2}

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A damped mass/spring system takes 14.0 s for its amplitude of the oscillator to decrease by a factor of 9. By what factor does t
fiasKO [112]

Answer:

The correct answer is "0.246".

Explanation:

Given that the amplitude is decreased by a factor of 9, then

A \rightarrow (A-\frac{A}{9} )

A \rightarrow \frac{8A}{9}

As we know,

Energy will be:

⇒  E_{1}=\frac{1}{2}KA^2

and,

⇒  E_{2}=\frac{1}{2}K(\frac{8A}{9} )^2

          =\frac{64KA^2}{162}

⇒  \Delta E=E_1-E_2

On putting the estimated values, we get

           =\frac{1}{2}KA^2-\frac{64KA^2}{162}

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3 years ago
An artificial satellite in a low orbit circles the earth every 98 minutes. what is its angular speed in rad/s?
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Kinematics practice problems Answers: 4. A race car is traveling at +76 m/s when is slows down at -9 m/s2 for 4
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The new velocity after 4 s is 40 m/s

The height of the spaceship above the ground after 5 seconds is 1,127.5 m

The given parameters for the first question;

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  • time of motion, t = 4 s

The new velocity after 4 s is calculated as;

v = u + at

v = 76 + (-9)(4)

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(5)

The given parameters;

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  • velocity of spaceship, u = 150 m/s
  • time of motion, t = 5

The height of the spaceship above the ground after 5 seconds is calculated as;

h_y = h_0 + ut - \frac{1}{2}gt^2\\\\h_y = 500 + (150\times 5) -  (0.5\times 9.8 \times 5^2)\\\\h_y = 1,127.5 \ m

Learn more here: brainly.com/question/24527971

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