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3 years ago

11

In Thomson's experiments with electron beams, when the magnetic force FM balanced the force of the electric field Fe, the veloci

ty of the beam was given by the ratio--- divided by--- .

1 answer:

Ganezh [65]3 years ago

7 0

In Thomson's experiment, when the magnetic force balanced the electric force, the velocity of the beam was
$v= \frac{E}{B}$
where E is the magnitude of the electric field and B the magnitude of the magnetic field.

Let's see why. The force exerted by the electric field of intensity E on each electron is
$F=eE$
where $e$ is the electron charge.
The force exerted by the magnetic field of intensity B on each electron is
$F=evB$
where v is the speed of the electrons.

When the two forces are balanced, we have:
$eE=evB$
from which we find
$v= \frac{E}{B}$

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4 years ago