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MAVERICK [17]
3 years ago
13

Which of the following describes the graph of y=\sqrt(-4x-36) compared to the parent square root function?

Mathematics
2 answers:
borishaifa [10]3 years ago
6 0

Answer:

Option D - Stretched by a factor of 2, reflected over the y-axis, and translated 9 units left.

Step-by-step explanation:

Given : The function y=\sqrt{-4x-36}

To find : Which of the following describes the graph of y=\sqrt{-4x-36}compared to the parent square root function?

Solution :

First we simplify the given expression

y=\sqrt{-4x-36}

y=\sqrt{4(-x-9)}

y=2\sqrt{-(x+9)}

→When we see the original square root function minus was taken outside x and 9 was added from x and 2 was multiplied to the entire function.

  • Multiplying 2 in the function will give you the stretched by a factor of 2.
  • g(x)=\sqrt{-x} shows the reflection about y-axis i.e, (x,y)→(-x,y).
  • If f(x)→f(x+b) then function is shifted left by unit b

        ⇒ g(x))→g(x+9) then function is shifted left by unit 9

Therefore, The graph of was stretched by a factor of 2, reflected over the y-axis, and translated 9 units left to obtain the graph of the function .

So, Option D is correct.

Travka [436]3 years ago
6 0

Answer:

D) stretched by a factor of 2, reflected over the y-axis, and translated 9 units left

Step-by-step explanation:

its right on edge

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1. Write this translation rule in symbols: 2 units to the right and 3 down.
babunello [35]

Answer:

C. (x + 2, Y - 3)

Step-by-step explanation:

C. (x + 2, Y - 3)

5 0
3 years ago
Within a computer service company, 20 percent of the male employees and 30 percent of the female employees attend night school.
Maksim231197 [3]

26% of all the employees attend night school

Step-by-step explanation:

The given is:

  • Within a computer service company, 20 percent of the male employees and 30 percent of the female employees attend night school
  • 40 percent of all employees are male

We need to find what percent of all the employees attend night school

Assume that the number of all employees is x

∵ The company has x employees

∵ 40 percent of all employees are male

- Find 40% of x

∵ 40% × x = \frac{40}{100} × x = 0.4 x

∴ The number of the male employees is 0.4 x

- Subtract 0.4 x from x to find the number of the female employees

∵ The number of female employees = x - 0.4 x = 0.6 x

∴ The number of the female employees is 0.6 x

∵ 20 percent of the male employees attend night school

- Multiply 20% by 0.4 x to find the number of male employees

   who attend night school

∴ The number of male who attend night school = 20% × 0.4 x

∴ The number of male who attend night school = \frac{20}{100} × 0.4 x

∴ The number of male who attend night school = 0.08 x

∵ 30 percent of the female employees attend night school

- Multiply 30% by 0.6 x to find the number of female employees

   who attend night school

∴ The number of female who attend night school = 30% × 0.6 x

∴ The number of male who attend night school = \frac{30}{100} × 0.6 x

∴ The number of male who attend night school = 0.18 x

Add the number of male and female who attend night school

∵ 0.08 x + 0.18 x = 0.26 x

∴ The number of male and female who attend night school is 0.26 x

- Find the percentage of 0.26 x of x

∵ \frac{0.26x}{x} × 100% = 26%

∴ 26% of all the employees attend night school

26% of all the employees attend night school

Learn more:

You can learn more about the percentage in brainly.com/question/6871421

#LearnwithBrainly

5 0
3 years ago
The hcf of 55 and 99 is expressible in the form of 55m - 99 then the value of m is​
GuDViN [60]

Answer:

2

Step-by-step explanation:

HCF(55,99)= 11

  • 55m-99=11
  • 55m=110
  • m=110/2
  • m=2
5 0
3 years ago
A student at a four-year college claims that mean enrollment at four-year colleges is higher than at two-year colleges in the Un
WINSTONCH [101]

Answer:

Part 1: The statistic

t=\frac{(\bar X_{1}-\bar X_{2})-\Delta}{\sqrt{\frac{\sigma^2_{1}}{n_{1}}+\frac{\sigma^2_{2}}{n_{2}}}} (1)  

And the degrees of freedom are given by df=n_1 +n_2 -2=35+35-2=68  

Replacing we got

t=\frac{(5135-4436)-0}{\sqrt{\frac{783^2}{35}+\frac{553^2}{35}}}}=4.31  

Part 2: P value  

Since is a right tailed test the p value would be:  

p_v =P(t_{68}>4.31)=0.000022 \approx 0.00002  

Comparing the p value we see that is lower compared to the significance level of 0.01 so then we can reject the null hypothesis and we can conclude that the mean for the four year college is significantly higher than the mean for the two year college and then the claim makes sense

Step-by-step explanation:

Data given

\bar X_{1}=5135 represent the mean for four year college

\bar X_{2}=4436 represent the mean for two year college

s_{1}=783 represent the sample standard deviation for four year college

s_{2}=553 represent the sample standard deviation two year college

n_{1}=35 sample size for the group four year college

n_{2}=35 sample size for the group two year college

\alpha=0.01 Significance level provided

t would represent the statistic (variable of interest)  

System of hypothesis

We need to conduct a hypothesis in order to check if the mean enrollment at four-year colleges is higher than at two-year colleges in the United States , the system of hypothesis would be:  

Null hypothesis:\mu_{1}-\mu_{2}\leq 0  

Alternative hypothesis:\mu_{1} - \mu_{2}> 0  

We can assume that the normal distribution is assumed since we have a large sample size for each case n>30. So then the sample mean can be assumed as normally distributed.

Part 1: The statistic

t=\frac{(\bar X_{1}-\bar X_{2})-\Delta}{\sqrt{\frac{\sigma^2_{1}}{n_{1}}+\frac{\sigma^2_{2}}{n_{2}}}} (1)  

And the degrees of freedom are given by df=n_1 +n_2 -2=35+35-2=68  

Replacing we got

t=\frac{(5135-4436)-0}{\sqrt{\frac{783^2}{35}+\frac{553^2}{35}}}}=4.31  

Part 2: P value  

Since is a right tailed test the p value would be:  

p_v =P(t_{68}>4.31)=0.000022  

Comparing the p value we see that is lower compared to the significance level of 0.01 so then we can reject the null hypothesis and we can conclude that the mean for the four year college is significantly higher than the mean for the two year college and then the claim makes sense

6 0
3 years ago
A doctor raised $35,602 to use for research. She later found out that she would need $69,600 to completely pay for it all.
antoniya [11.8K]
The doctor has 35,602 and she needs 69,600.

We need to do subtraction to find out how much more she needs to raise.

69,600 - 35,602 = ?

69,600 - 35,602 = 33,998

The doctor needs to raise $33,998 more.

Your final answer is A. $33,998
7 0
3 years ago
Read 2 more answers
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