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3 years ago

PLEASE HELP! Given that (1,-8) is on the graph of f(x), find the corresponding point for the function 1/2f(x)

Mathematics

1 answer:

erma4kov [3.2K]3 years ago

6 0

Answer:

f=−16

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

1/ 2 f=−8

Step 2: Multiply both sides by 2.

2*( 1 /2 f ) = (2)*(−8)

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At a cake sale, David bought 3 cakes and paid $10.50. At the same price, Lisa bought 4 cakes and 8 cookies and paid $14.80. What

Olin [163]

Price of a Cake

10.5/3= 3.5

1 Cake = $3 and 5 cents, 3.5

Price of a cookie

3.5*4=14

14 out of 14.80 was the cost of 4 cakes

Which leaves us with 0.8

8/0.8= 0.1

The Price of 1 cookie is 0.1

1 Cake: 3.5

1 Cookie: 0.1

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3 years ago

What number is missing from the table of equivalent ratios

denpristay [2]

8 is missing for the table

8 0

2 years ago

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Can someone please explain to me how to solve this?

lyudmila [28]

I hope this helps you

x= -2

h (-2)= 3. (-2)+1

h (-2)=-6+1

h (-2)= -5

4 0

3 years ago

(1.)Find the slope of the line that passes through the given pair of points. (If an answer is undefined, enter UNDEFINED.) (?a +

jekas [21]

Answer:

1. The slope of the line is $m=\frac{-2b+3}{2a}$ .

2. The value of a is 18.

Step-by-step explanation:

If a line passes through two points, then the slope of the line is

$m=\frac{y_2-y_1}{x_2-x_1}$

(1)

It is given that the line passes through the points (-a + 3, b - 3) and (a + 3, -b). So, the slope of the line is

$m=\frac{-b-(b-3)}{a+3-(-a+3)}$

$m=\frac{-b-b+3}{a+3+a-3)}$

$m=\frac{-2b+3}{2a}$

The slope of the line is $m=\frac{-2b+3}{2a}$ .

(2)

If the line passing through the points (a, 1) and (6, 5), then the slope of the line is

$m_1=\frac{5-1}{6-a}=\frac{4}{6-a}$

If the line passing through the points (2, 7) and (a + 2, 1), then the slope of the line is

$m_2=\frac{1-7}{a+2-2}=\frac{-6}{a}$

The slopes of two parallel lines are same.

$m_1=m_2$

$\frac{4}{6-a}=\frac{-6}{a}$

On cross multiplication we get

$4a=-6(6-a)$

$4a=-36+6a$

$4a-6a=-36$

$-2a=-36$

Divide both sides by -2.

$a=18$

Therefore the value of a is 18.

8 0

3 years ago

Quadrilateral EFGH has coordinates E(2a, 2a), F(3a, a), G(2a, 0), and H(0, 0). Find the midpoint of he

Gre4nikov [31]

The formula of the midpoint of HE:
$\left(\dfrac{x_H+x_E}{2};\ \dfrac{y_H+y_E}{2}\right)$

We have H(0; 0) and E(2a; 2a). Substitute:
$\left(\dfrac{0+2a}{2};\ \dfrac{0+2a}{2}\right)=(a;\ a)$

4 0

3 years ago

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