Answer:
4 kg of force
Explanation:
Force = (mass x distance to fulcrum) / length of fulcrum to end
Subsitute values
F = (10 x 20)/50
F =4
Answer:

Explanation:
The work (W) done by the gas can be calculated using the following equation:

<u>Where:</u>
p: is the pressure
[tex}V_{f}[/tex]: is the final volume
[tex}V_{i}[/tex]: is the initial volume
In the first process, the work done by the gas is:

Since the volume remains constant, the total work done by the gas is equal to zero.
In the second process, the work done by the gas is:
Now, the total work done by the gas during both processes is:

Therefore, the total work done by the gas during both processes is - 24 kJ.
I hope it helps you!
Answer:
The time taken for the train to cross the bridge is 9.01 s
Explanation:
Given;
length of the train, L₁ = 90 m
length of the bridge, L₂ = 0.06 m
speed of the train, v = 10 m/s
Total distance to be traveled, = L₁ + L₂
= 90 m + 0.06 m
= 90.06 m
Time of motion = Distance / speed
Time of motion = 90.06 / 10
Time of motion = 9.006 s ≅ 9.01 s
Therefore, the time taken for the train to cross the bridge is 9.01 s
Answer:
force is of the LINEAR type
Explanation:
In simple harmonic movements the restoring force is of the Hooke e-force type, which has the form
F = - k (x-x₀)
where x₀ is the initial length of the spring.
Therefore we can see this force is of the LINEAR type
Answer:
Vrms = 291 m/s
Explanation:
The root mean square velocity or vrms is the square root of the average square velocity and is. vrms=√3RTM. Where M is equal to the molar mass of the molecule in kg/mol.
Temperature = 365 K
Root mean square velocity = ?
molar mass of oxygen = 16 g/mol.
But xygen gas (O2) is comprised of two oxygen atoms bonded together. Therefore:
molar mass of O2 = 2 x 16
molar mass of O2 = 32 g/mol
Convert this to kg/mol:
molar mass of O2 = 32 g/mol x 1 kg/1000 g
molar mass of O2 = 3.2 x 10-2 kg/mol
Molar mass of Oxygen = 3.2 x 10-2 kg/mol
Vrms = √[3(8.3145 (kg·m2/sec2)/K·mol)(365 K)/3.2 x 10-2 kg/mol]
Vrms = 291 m/s