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andrey2020 [161]
4 years ago
13

What is the mass of H2O in 3 moles?

Chemistry
1 answer:
ss7ja [257]4 years ago
4 0

The answer is 18.02 grams


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Metals are used in many products because of the characteristic properties that most metals have. Which product requires the high
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Metals are used in many products because of the characteristic properties that most metals have. The product that requires the high luster of metals is a mirror. Luster is used to describe something that reflect light off a surface. Metals are known to have the quality of reflecting light from its surface therefore it is a good material for the said product.
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Nicotine is a poisonous, addictive compound found in tobacco. A sample of nicotine contains 6.16 mmol of C, 8.56 mmol of H, and
tiny-mole [99]

C₁₀H₁₄N₂ is the empirical formula.

In chemistry, the empirical formula of a chemical compound is the simplest whole number ratio of atoms present in a compound.

<h3>Tell us about the empirical formula.</h3>

The empirical formula of a chemical compound in chemistry is the simplest whole number ratio of atoms in a compound. Two simple instances of this concept are the empirical formulas of sulfur monoxide (SO) and disulfur dioxide (S2O2).

Its empirical formula is the simplest whole number ratio of each type of atom in the compound. Data about the mass of each component in a compound or the composition's percentage can be used to calculate it.

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8 0
2 years ago
Given the following at 25C calculate delta Hf for HCN (g) at 25C. 2NH3 (g) +3O2 (g) + 2CH4 (g) ---&gt; 2HCN (g) + 6H2O (g) delta
AysviL [449]

<u>Answer:</u> The \Delta H_f for HCN (g) in the reaction is 135.1 kJ/mol.

<u>Explanation:</u>

Enthalpy change is defined as the difference in enthalpies of all the product and the reactants each multiplied with their respective number of moles. The equation used to calculate enthalpy change is of a reaction is:

\Delta H_{rxn}=\sum [n\times \Delta H_f(product)]-\sum [n\times \Delta H_f(reactant)]

For the given chemical reaction:

2NH_3(g)+3O_2(g)+2CH_4(g)\rightarrow 2HCN(g)+6H_2O(g)

The equation for the enthalpy change of the above reaction is:

\Delta H_{rxn}=[(2\times \Delta H_f_{(HCN)})+(6\times \Delta H_f_{(H_2O)})]-[(2\times \Delta H_f_{(NH_3)})+(3\times \Delta H_f_{(O_2)})+(2\times \Delta H_f_{(CH_4)})]

We are given:

\Delta H_f_{(H_2O)}=-241.8kJ/mol\\\Delta H_f_{(NH_3)}=-80.3kJ/mol\\\Delta H_f_{(CH_4)}=-74.6kJ/mol\\\Delta H_f_{(O_2)}=0kJ/mol\\\Delta H_{rxn}=-870.8kJ

Putting values in above equation, we get:

-870.8=[(2\times \Delta H_f_{(HCN)})+(6\times (-241.8))]-[(2\times (-80.3))+(3\times (0))+(2\times (-74.6))]\\\\\Delta H_f_{(HCN)}=135.1kJ

Hence, the \Delta H_f for HCN (g) in the reaction is 135.1 kJ/mol.

8 0
3 years ago
What is the velocity of a 485 kg elevator that has 5900 J of energy?
Ganezh [65]

The velocity of a 485 kg elevator that has 5900 J of energy is 108.6 m/s

<h3>What is the velocity of the elevator?</h3>

A moving elevator possesses kinetic energy due to its motion.

The velocity of the elevator is calculated from the formula of kinetic energy.

The kinetic energy formula is : Kinetic energy = ¹/₂mv₂

The velocity, v = √2KE/m

v = √(2 * 5900/485)

v = 108.6 m/s

In conclusion, the velocity of the elevator is calculated from the kinetic energy and mass of the elevator.

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2 years ago
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