Answer:
10 kg of water was added to the 20 kg of seawater to dilute it from 3% to 2%. Hope this helps!!!!!!
The compound formed when nitrogen combines with hydrogen is ammonia.
A chemical reaction is said to have occurred when two elements combine according to a given reaction equation.
In this case, Sanju wants to combine nitrogen and hydrogen. The reaction takes place according to the equation;
N2 + 3H2 ----> 2NH3
The product formed in the reaction is ammonia.
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Assuming that the circuit is a simple series circuit we can determine what the current is through the circuit by using the basic relationship of
V = IR
I = V/R = 60 V/12 ohms = 5 Amperes
The current in the circuit is 5 A.
They have similar properties.Bromine and Chlorine both have equal chemical properties. They both have 7.electrons in the outermost energy level. They both gain 1 electron to get the. noble gas configuration.Cl and Br have same chemical properties. They have 7,valence electrons. They both are non-metals. Bromine and chlorine are in group VII A, which could also be designated Group 7a, of the narrow form periodic table that was commonly used before 1980. Most chemists now prefer a wide form periodic table, in which these elements are in column 17. The periodic table has been set up to illustrate the repeating nature of the elements as we progress along their atomic number. Cl (chlorine) and Br (bromine) are very similar because they both have seven valence electrons, and both need only one more to be like a noble gas. (The need to have eightelectrons in the outer main shell is called the octet rule, and the reason for <span>this is understood by scientists, but is complicated.) HOPE IT HELPED
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Answer:
Qsp > Ksp, BaCO3 will precipitate
Explanation:
The equation of the reaction is;
Na2CO3 + BaBr2 -------> 2NaBr + BaCO3
Since BaCO3 may form a precipitate we can determine the Qsp of the system.
Number of moles of Na2CO3 = 0.96g/106 g/mol = 9.1 * 10^-3 moles
concentration of NaCO3 = number of moles/volume of solution = 9.1 * 10^-3 moles/10 L = 9.1 * 10^-4 M
Number of moles of BaBr2 = 0.20g/297 g/mol = 6.7 * 10^-4 moles
concentration of BaBr2 = 6.7 * 10^-4 moles/10 L = 6.7 * 10^-5 M
Hence;
[Ba^2+] = 6.7 * 10^-5 M
[CO3^2-] = 9.1 * 10^-4 M
Qsp = [6.7 * 10^-5] [9.1 * 10^-4]
Qsp = 6.1 * 10^-8
But, Ksp for BaCO3 is 5.1*10^-9.
Since Qsp > Ksp, BaCO3 will precipitate