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topjm [15]
1 year ago
12

Nicotine is a poisonous, addictive compound found in tobacco. A sample of nicotine contains 6.16 mmol of C, 8.56 mmol of H, and

1.23 mmol of N [1 mmol (1 millimole) = 10⁻³ mol]. What is the empirical formula of nicotine?
Chemistry
1 answer:
tiny-mole [99]1 year ago
8 0

C₁₀H₁₄N₂ is the empirical formula.

In chemistry, the empirical formula of a chemical compound is the simplest whole number ratio of atoms present in a compound.

<h3>Tell us about the empirical formula.</h3>

The empirical formula of a chemical compound in chemistry is the simplest whole number ratio of atoms in a compound. Two simple instances of this concept are the empirical formulas of sulfur monoxide (SO) and disulfur dioxide (S2O2).

Its empirical formula is the simplest whole number ratio of each type of atom in the compound. Data about the mass of each component in a compound or the composition's percentage can be used to calculate it.

To learn more about empirical formula visit:

brainly.com/question/14044066

#SPJ4

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A car traveling with constant speed travels 150 km in 7200 s. What is the speed of the car?
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3 years ago
2) Examine the molecules below.<br> Circle the molecules that can also be classified as compounds.
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4 0
2 years ago
Can someone pls help me with this question
artcher [175]

Answer:

The answer to your question is 24.325

Explanation:

Data

Magnesium-24  Abundance = 78.70%

Magnesium-25  Abundance = 10.13%

Magnesium-26  Abundance = 11.17%

Process

1.- Convert the abundance to decimals

Magnesium-24  Abundance = 78.70/100 = 0.787

Magnesium-25  Abundance = 10.13/100 = 0.1013

Magnesium-26  Abundance = 11.17/100 = 0.1117

2.- Write an equation

Average atomic mass = (Atomic mass-1 x Abundance 1) + (Atomic mass 2 x

                                       Abundance-2) + (Atomic mass 3 x Abundance 3)

3.- Substitution

Average atomic mass = (24 x 0.787) + (25 x 0.1013) + (26 x 0.1117)

4.- Simplification

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5.- Result

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5 0
3 years ago
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