Answer:
C₆H₆ + 3HNO₃ → C₆H₃N₃O₆ + 3H₂O
Explanation:
The reaction is:
Benzene + Nitric acid → Water + ?
Let's determine the ? compound
Molar mass 213 g/mol
33.8g of C in 100 g of compound |
1.42 g of H in 100g of compound | _ Percent composition
19.7 g of N in 100g of compound |
45.1 g of O in 100g of compound |
We propose these rule of three:
In 100 g of compound we have 33.8 g C, 1.42 g H, 19.7g N and 45.1g O
Therefore in 213g of compound we must have:
(213 . 33.8) / 100 = 72 g of C
(213 . 1.42) / 100 = 3 g of H
(213 . 19.7) / 100 = 42 g of N
(213 . 45.1) / 100 = 96 g of O
Now, we convert the mass to moles:
72 g of C . 1 mol / 12g = 6 C
3 g of H . 1 mol / 1g = 3 H
42 g of N . 1 mol / 14 g = 3 N
96 g of O . 1 mol / 16 g = 6 O
Molecular formula is C₆H₃N₃O₆. So the balanced reaction will be:
C₆H₆ + 3HNO₃ → C₆H₃N₃O₆ + 3H₂O
