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ivann1987 [24]
2 years ago
12

A student is monitoring the pressure of a gas in a rigid container. The amount of gas particles and the volume of the container

are held constant. How will the pressure be affected if the container is cooled over time?
Chemistry
2 answers:
daser333 [38]2 years ago
7 0

Answer:

the gas pressure will decrease

Explanation:

saveliy_v [14]2 years ago
3 0
Chances is it will drop because in the cold gas cannot expand or rise while in the heat it expands and rises 
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Please answer this question
Svetradugi [14.3K]

Answer:

............................................

Explanation:

............................................

7 0
2 years ago
Read 2 more answers
In which state(s) of matter are the<br> particles free to move at Gut relative to<br> one another?
Colt1911 [192]
The answer is gas only.
hope this helps!
8 0
3 years ago
Calculate the volume in milliliters of a 0.420mol / L barlum chlorate solution that contains 25.0 g of barium chlorate (Ba(ClO 3
Pachacha [2.7K]

<u>Answer:</u> The volume of barium chlorate is 195.65 mL

<u>Explanation:</u>

To calculate the volume of solution, we use the equation used to calculate the molarity of solution:

\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}

Given mass of barium chlorate = 25.0 g

Molar mass of barium chlorate = 304.23 g/mol

Molarity of solution = 0.420 mol/L

Volume of solution = ?

Putting values in above equation, we get:

0.420mol/L=\frac{25.0\times 1000}{304.23\times V}\\\\V=\frac{25.0\times 1000}{304.23\times 0.420}=195.65mL

Hence, the volume of barium chlorate is 195.65 mL

6 0
3 years ago
Помогите пожалуйста или с первым вопросом или со вторым. Буду очень благодарна, т.к. это мой зачет... :С
Bess [88]
Hsiaqoanwbwiso iDisks
5 0
3 years ago
in the following reaction, how many grams of benzene (C6H6) will produce 42 grams of CO2? 2C6H6 + 15O2 → 12CO2 + 6H2O
Mrrafil [7]

Answer: -

12.41 g

Explanation: -

Mass of CO₂ = 42 g

Molar mass of CO₂ = 12 x 1 + 16 x 2 = 44 g / mol

Number of moles of CO₂ = \frac{42}{44 g/mol}

= 0.9545 mol

The balanced chemical equation for this process is

2C₆H₆ + 15O₂ → 12CO₂ + 6H₂O

From the balanced chemical equation we see

12 mol of CO₂ is produced from 2 mol of C₆H₆

0.9545 mol of CO₂ is produced from \frac{2 mol C6H6 x 0.9545 mol  CO2}{12 mol CO2}

= 0.159 mol of C₆H₆

Molar mass of C₆H₆ = 12 x 6 + 1 x 6 =78 g /mol

Mass of C₆H₆ =Molar mass x Number of moles

= 78 g / mol x 0.159 mol

= 12.41 g

8 0
3 years ago
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