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Masteriza [31]
3 years ago
11

A fixed quantity of gas fills a volume of 10.6 liters at 638 torr and 83 C. Find the volume it will occupy if the pressure is 10

76 torr and the temperature rises to 96 C
Chemistry
1 answer:
sukhopar [10]3 years ago
5 0
According to this formula:
(P1V1) / T1 = (P2V2) / T2

convert T from C° to Kelvin:
T1 = 83 + 273 = 356 K
T2= 96 + 273 = 369 K

convert P from torr to atm:
1 torr = 0.00131578947 atm<span>
p1 = 0.839474 atm
P2 = 1.415789 atm
By substitution in the previous formula:
(0.839474 x 10.6 ) / (356) = ( 1.415789 x V2 ) / 369
So:
V2 = 6.5 L</span>
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What total volume of ozone measured at a pressure of 24.5 mmHg and a temperature of 232 K can be destroyed when all of the chlor
ddd [48]

Answer:

1.75272\ \text{m}^3

Explanation:

The breakdown reaction of ozone is as follows

CF_3Cl + UV \rightarrow CF_3 + Cl

Cl + O_3 \rightarrow ClO + O_2

O_3 + UV \rightarrow O_2 + O

ClO + O \rightarrow Cl + O_2

It can be seen that 2 moles of ozone is required in the complete cycle

So for 10 cycles, 20 moles of ozone is required

m = Mass of CF_3Cl = 15.5 g

M = Molar mass of CF_3Cl = 104.46 g/mol

P = Pressure = 24.5 mmHg

T = Temperature = 232 K

R = Gas constant = 62.363\ \text{L mmHg/K mol}

Number of moles is given by

n=\dfrac{m}{M}\\\Rightarrow n=\dfrac{15.5}{104.46}\\\Rightarrow n=0.1484\ \text{moles}

20\ \text{moles} = 20\times 0.1484 = 2.968\ \text{moles}

From ideal gas law we have

PV=nRT\\\Rightarrow V=\dfrac{nRT}{P}\\\Rightarrow V=\dfrac{2.968\times 62.363\times 232}{24.5}\\\Rightarrow V=1752.72\ \text{L}=1.75272\ \text{m}^3

For 20 cycles of the reaction the volume of the ozone is 1.75272\ \text{m}^3.

7 0
3 years ago
A cup of coffee has 71 mL of coffee and 127 mL of water. What is the percent volume of the coffee solution?
Anna [14]

Answer:

35.9%

Explanation:

The percent volume of the coffee solution can be calculated as follows:

% volume of coffee solution = volume of coffee/total volume of coffee solution × 100

According to this question, a cup of coffee has 71 mL of coffee and 127 mL of water. This means that, the total volume of coffee solution is;

71mL + 127mL = 198mL

% volume = 71/198 × 100

= 0.359 × 100

Percent volume of coffee solution = 35.9%

3 0
3 years ago
If 97.3 L of NO2 forms measured at 35 C and 632 mm Hg. What is the percent yield?
enyata [817]
<span>a. Use PV = nRT and solve for n = number of mols O2. 
mols NO = grams/molar mass = ? 

 Using the coefficients in the balanced equation, convert mols O2 to mols NO2. Do the same for mols NO to mols NO2. It is likely that the two values will not be the same which means one is wrong; the correct value in LR (limiting reagent) problems is ALWAYS the smaller value and the reagent producing that value is the LR. 

b. 
Using the smaller value for mols NO2 from part a, substitute for n in PV = nRT, use the conditions listed in part b, and solve for V in liters. This will give you the theoretical yield (YY)in liters. The actual yield at these same conditions (AY) is 84.8 L. 

</span>and % will be 60%.
3 0
3 years ago
The element krypton (symbol: Kr) has several radioactive isotopes. Here
Dovator [93]

Answer:

Kr-81 is most stable because of its high half lige and kr-73 is the most radioactive because of its least half life

Explanation:

Stability is directly proportional to half life of a reaction

3 0
2 years ago
Name the following compound:
postnew [5]
I don't know yaaarrrrrrrrrrrrrrrr
8 0
3 years ago
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