Complete this example: A 0.67 molal solution was

Studio

coldgirl [10]

Answer:

0.895 g/mL

Explanation:

Step 1: Given data

Mass of liquid Z (m): 2.763 lb

Volume of liquid Z (V): 5.93 cups

Step 2: Convert "m" to grams

We will use the relationship 1 lb = 453.59 g.

$2.763 lb \times \frac{453.59 g}{1lb} = 1,253g$

Step 3: Convert "V" to milliliters

We will use the relationship 1 cup = 236.59 mL.

$5.93cup \times \frac{236.59mL}{1cup} = 1.40 \times 10^{3} mL$

Step 4: Calculate the density of the liquid Z

The density (ρ) of the liquid Z is equal to its mass divided by its volume.

$\rho = \frac{m}{V} = \frac{1,253g}{1.40 \times 10^{3}mL } = 0.895 g/mL$

4 0

3 years ago

What is the smallest substance? 1 .mixture 2 .compound 3 .element

Andrew [12]

Number 3 it’s element

8 0

3 years ago

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In the compound h2s hydrogen has an oxidation number of 1+ and sulfur has an oxidation number of

elena-14-01-66 [18.8K]

Oxidation number is defined as the total number of electrons that are gained or lost by the atom to form a chemical bond.
the oxidation number of the compound H₂S is 0.
the sum of the oxidation numbers of the individual elements should add up to the oxidation number of the compound.

(oxidation number of H x 2 H ions) + oxidation number of S = 0
since we know the oxidation number of H, lets name the oxidation number of S = x
(+1 * 2 )+ (x) = 0
2 + x = 0
x = -2
oxidation number of S is -2

3 0

3 years ago

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Composition variable

Brrunno [24]

Answer:

c. Substance

Explanation:

A composition variable is an intensive property that indicates the relative amount of a particular species or substance in a phase.

5 0

3 years ago

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1. For every 5.00 mL of milk of magnesia there are 400. mg of magnesium hydroxide. How many mL of milk of magnesia do we need to

forsale [732]

Answer:

1. 6.50mL

2. pH = 13.097

Explanation:

1. The neutralization of HCl with Al(OH)₃ is:

3HCl + Al(OH)₃ → Al(Cl)₃ + 3H₂O

40.0mL ≡ 0.0400L of 0.500M HCl are:

0.0400L × (0.500mol / L) = 0.0200 moles of HCl

Based on the neutralization, 3 moles of HCl react with 1 mole of Al(OH)₃, thus, the moles of Al(OH)₃ that react with 0.0200 mol of HCl are:

0.0200mol HCl × (1mol Al(OH)₃ / 3mol HCl) = 0.00667 moles of Al(OH)₃. In grams:

0.00667 moles Al(OH)₃ × (78g / 1mol) = 0.520g of Al(OH)₃ ≡ 520mg

As 5.00mL of milk magnesia contain 400mg of Al(OH)₃, the mL of milk magnesia required for a complete reaction are:

520 mg Al(OH)₃ × (5.00mL / 400mg) = 6.50mL

2. The reaction of lithium hydroxide (LiOH) with perchloric acid (HClO₄) is:

HClO₄ + LiOH → LiClO₄ + H₂O

The reaction is 1:1.

Moles of LiOH and HClO₄ are:

LiOH: 0.0500L × (0.350mol / L) = 0.0175 moles of LiOH

HClO₄: 0.0300L × (0.250mol / L) = 0.0075 moles of HClO₄

Assuming the reaction goes to completion, moles of LiOH that remains are:

0.0175 mol - 0.0075 mol = 0.0100 moles of LiOH. The total volume is 80.0mL, 0.0800L. Thus, molarity of LiOH is:

0.0100 mol / 0.0800L = 0.125 M of LiOH

It is possible to obtain the pOH of the solution thus:

pOH = -log (OH) = -log 0.125M = 0.903

As pH = 14- pOH,

pH = 14 - 0.903 = 13.097

I hope it helps!

3 0

3 years ago