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Novosadov [1.4K]
3 years ago
7

How do you know that (-3/4) (-8a) + (-3/4) (-12) is equivalent to both -3/4(-8a - 12) and 6a + 9?

Mathematics
2 answers:
Mademuasel [1]3 years ago
6 0

Answer:

Step-by-step explanation:

We know these outcomes by applying Order of Operations rules.

(-3/4) (-8a) + (-3/4) (-12) after performing the two indicated multiplications is

6a + 9.  

The original (-3/4) (-8a) + (-3/4) (-12) can be factored as follows:

(-3/4) (-8a) + (-3/4) (-8a - 12)  =  (-3/4)(-8a - 12)

Marta_Voda [28]3 years ago
5 0

Answer:

,

Step-by-step explanation:

\frac{-3}{4}*(-8a) + (\frac{-3}{4})* (-12) = (-3)*(-2a) + (-3) * 3\\ = 6a + 9

Here, we simplified  the expression.

\frac{-3}{4}*(-8a) + (\frac{-3}{4})(-12) = (\frac{-3}{4})(-8a - 12)

Here, (-3/4), the common factor for two terms is taken outside.

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f(x)=10-x/4

Step-by-step explanation:

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3 years ago
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Answer pls need help immediately
juin [17]

They are supplementary so they add up to 180

The equation would be x+96+5x = 180

Combine the like terms.

6x+96 = 180

Subtract 96 on both sides.

6x=84

Divide both sides by 6.

x=14

3 0
3 years ago
Sqrt(3x)-1=-4<br><br> 1.)x=3<br><br> 2.)x=-3<br><br> 3.) no solution<br><br> 4.)x= 25/3
shtirl [24]
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8 0
4 years ago
2. Harry just deposited $1500 into a savings account giving 6% interest compounded quarterly.a) How much will be in the account
Studentka2010 [4]

The formula for compound interest is:

\begin{gathered} A=P(1+\frac{r}{n})^{nt} \\ \text{where,} \\ A=\text{ Final amount} \\ r=\text{ Interest rate} \\ n=\text{ Number of times interest applied per period} \\ t=\text{ Number of time period elapsed} \\ P=\text{ Intial principal balance} \end{gathered}

Given data:

\begin{gathered} P=\text{ \$1500} \\ r=6\text{ \%}=0.06 \\ n=4\text{ times (compounded quarterly)} \end{gathered}

a. After ten years, that is t = 10 years, the amount in the account will be

\begin{gathered} A=1500(1+\frac{0.06}{4})^{4\times10} \\ A=\text{ }1500(1+0.015)^{40} \\ A=\text{ }1500(1.015)^{40} \\ A=\text{ \$2721.03} \end{gathered}

b. After twenty years, that is t = 20 years, the amount in the account will be:

\begin{gathered} A=1500(1+\frac{0.06}{4})^{4\times20} \\ A=1500(1.015)^{4\times20} \\ A=1500(1.015)^{80} \\ A=\text{ \$}4935.99 \end{gathered}

c. The time it takes for Harry's initial account value to double will be:

\begin{gathered} A=2\text{ x initial value = 2 }\times\text{ \$1500 = \$3000} \\ 3000=1500(1.015)^{4t} \\ (1.015)^{4t}=\frac{3000}{1500} \\ (1.015)^{4t}=2 \\ \text{ Find the logarithm of both sides} \\ \ln (1.015)^{4t}=\ln 2 \\ 4t=\frac{\ln 2}{\ln 1.015} \\ 4t=46.56 \\ t=\frac{46.56}{4}=11.64 \end{gathered}

Therefore, the time it takes Harry's initial account to double is approximately 11 years

8 0
1 year ago
Width = 18 in, length = 1.92 ft Area = in?​
Genrish500 [490]

34.56

Just multiply them, and you will get the answer.

5 0
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