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kipiarov [429]
3 years ago
13

What number should be placed in the box to help complete the division calculation?

Mathematics
1 answer:
vovangra [49]3 years ago
6 0

Answer:

160

Step-by-step explanation:

226

-160

____

66

-64 (4 in the quotient)

____

2

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Whats the answers can anyone answer this question please​
topjm [15]

Answer:

1. B

2. A

Step-by-step explanation:

1.

10^{-2} means that you move the decimal back two times

B is the only option that represents that correctly.

2.

5 * 10^{4} = 50000

2.5 * 10^{2} = 250

50000/250 = 200

Out of the options, A is the only option in which the equation also equals 200.

4 0
2 years ago
Simplify the expression 4(x + 5) - 3(7 + x)
Anvisha [2.4K]

Answer:

x-1

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
water weighs about 8.34 pounds per gallon. About how many ounces per gallon is the weight of the water?
notka56 [123]
Use a conversion factor and turn pounds to ounces. 1 pound = 16 ounces so
\frac{8.34pounds}{gallon} \times \frac{16 ounces}{ 1 pound} =133.44 \frac{ounces}{gallon}
3 0
3 years ago
Kyle crawled 49.8 feet in 6 minutes, how far did he crawl every minute…
Blizzard [7]

Answer:

assuming that kyle crawled at the same pace for six minute then it would be 8.3 feet each minute

Step-by-step explanation:

8 0
3 years ago
I need help please I don’t understand
defon

9514 1404 393

Answer:

  1. ∠EDF = 104°

  2. arc FG = 201°

  3. ∠T = 60°

Step-by-step explanation:

There are a couple of angle relationships that are applicable to these problems.

  • the angle where chords meet is half the sum of the measures of the intercepted arcs
  • the angle where secants meet is half the difference of the measures of the intercepted arcs

The first of these applies to the first two problems.

1. ∠EDF = 1/2(arc EF + arc UG)

  ∠EDF = 1/2(147° +61°) = 1/2(208°)

  ∠EDF = 104°

__

2. ∠FHG = 1/2(arc FG + arc ES)

  128° = 1/2(arc FG +55°) . . . substitute given information

  256° = arc FG +55° . . . . . . multiply by 2

  201° = arc FG . . . . . . . . . subtract 55°

__

3. For the purpose of this problem, a tangent is a special case of a secant in which both intersection points with the circle are the same point. The relation for secants still applies.

  ∠T = 1/2(arc FS -arc US)

  ∠T = 1/2(170° -50°) = 1/2(120°)

  ∠T = 60°

3 0
3 years ago
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