Question

The sum of three consecutive numbers is 153. What is the smallest of the three numbers ?

Answer 1

$n;\ n+1;\ n+2 - \text{three consecutive numbers}\\\\(n)+(n+1)+(n+2)=153\\\\n+n+1+n+2=153\\\\3n+3=153\ \ \ \ |-3\\\\3n=150\ \ \ \ |:3\\\\n=50$


Answer: 50