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Kaylis [27]
3 years ago
12

28. Sound can be heard around a corner because of

Physics
1 answer:
Lesechka [4]3 years ago
5 0

Answer:

Diffraction of sound wavelengths.

Explanation:

Diffraction-A wave is able to bend around a corner due to the effects of diffraction. sound aves are capable of bending around corners in the same magnitude as it's wavelength making it possible to hear sounds around corners.

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3 years ago
What is the magnetic field amplitude of an electromagnetic wave whose electric field amplitude is 10v/m?
Nitella [24]

Answer:

3.33\cdot 10^{-8} T

Explanation:

For an electromagnetic wave, the relationship between magnetic field amplitude and electric field amplitude is given by

E=cB

where

E is the amplitude of the electric field

c is the speed of light

B is the amplitude of the magnetic field

For the electromagnetic wave in this problem, we have

E = 10 V/m is the amplitude of the electric field

So if we solve the formula for B, we find the amplitude of the magnetic field:

B=\frac{E}{c}=\frac{10 V/m}{3\cdot 10^8 m/s}=3.33\cdot 10^{-8} T

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3 years ago
If you help me with the correct answer I will give you the brainlist
gulaghasi [49]

Answer:

1. A force is a push or pull upon an object resulting from the object's interaction with another object.  

Explanation:

6 0
3 years ago
In a certain region of space, the electric potential is V(x,y,z)=Axy-Bx^2+Cy , where A,B , and C are positive constants.a) Calcu
laiz [17]

Answer:

a)  Eₓ = - A y + 2B x , b)  Ey = -Ax –C , c) Ez = 0 , d) The correct answer is 3

Explanation:

The electric field and the electric power are related

                    E = - dV / ds

a) Let's find the electric field on the x axis

                  Eₓ = - dV / dx

                  dV / dx = A y - B 2x

                  Eₓ = - A y + 2B x

b) calculate the electric field on the y-axis

                Ey = - dV / dy

                dV / dy = A x + C

                Ey = -Ax –C

c) the electric field on the z axis

              dv / dz = 0

              Ez = 0

.d) at which point the electric field is zero

Since the electric field is a vector quantity all components must be zero

X axis

              0 = = - A y + 2B x

              y = 2B / A x

Axis y

             0 = -Ax –C

              .x = -C / A

We substitute this value in the previous equation

             .y = 2B / A (-C / A)

             .y = 2 B C / A2

The correct answer is 3

6 0
4 years ago
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