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Masteriza [31]
1 year ago
9

25. IF THE ROADWAY IS WET AND THE CAR STARTS TO SKID, YOU SHOULD: A. Slow down by pumping the brakes quickly and firmly B. Slow

down by shifting to a lower gear C. Slowly ease your foot off the gas pedal
Physics
1 answer:
AnnZ [28]1 year ago
5 0

If the roadway is wet and the cars starts to skid, one should slow down by shifting to lower gear. The correct option is B.

<h3>What are gears?</h3>

A gear is component used to transmit motion. They are used in cars, trucks, machines, bicycles, etc.

For a car to avoid skidding on the wet roads, one must drive the car slowly. This can be done by shifting the gear to the lower one. This will help car to keep balance when brakes are applied on wet roads.

Thus, the correct option is B.

Learn more about gears.

brainly.com/question/14455728

#SPJ1

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How many excess electrons must be present on each sphere if the magnitude of the force of repulsion between them is 4.57×10−21 n
hichkok12 [17]

Answer:

891 excess electrons must be present on each sphere

Explanation:

One Charge = q1 = q

Force = F = 4.57*10^-21 N  

Other charge = q2 =q

Distance = r = 20 cm = 0.2 m  

permittivity of free space = eo =8.854×10−12 C^2/ (N.m^2)  

Using Coulomb's law,

F=[1/4pieo]q1q2/r^2

F = [1/4pieo]q^2 / r^2

q^2 =F [4pieo]r^2

q =  r*sq rt F[4pieo]

 q=0.2* sq rt[ 4.57 x 10^-21]*[4*3.1416*8.854*10^-12]

q = 1.42614*10^ -16 C

number of electrons = n = q/e=1.42614*10^ -16 /1.6*10^-19

n =891

 891 excess electrons must be present on each sphere  

5 0
2 years ago
a uniform metre rule is pivoted at its centre and weights of 5 N and 12 N are hung at the 3 cm and 5 cm marks respectively. how
schepotkina [342]

In order to balance the stick on the pivot, the total "moments" must be equal on both sides.  A "moment" is (a weight) x (its distance from the center).

for the 5N weight: Moment = (5N) x (3 cm) = 15 N-cm

for the 12N weight: Moment = (12N) x (5 cm) = 60 N-cm

Sum of the moments trying to pull the stick down on that side = 75 N-cm

Whatever we hang on the other side has to provide a moment of 75 N-cm in the other direction.  We have a 25N weight. Where should we hang it ?  

(25N) x (distance from the pivot) = 75 N-cm

Distance from the pivot = (75 N-cm) / (25 N)

<em>Distance from the pivot =  3 cm </em>

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