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MissTica
2 years ago
14

light spring of force constant k = 158 N/m rests vertically on the bottom of a large beaker of water (Figure a). A 4.36-kg block

of wood (density = 650 kg/m3) is connected to the spring, and the block-spring system is allowed to come to static equilibrium (Figure b). What is the elongation ΔL of the spring?
Physics
1 answer:
Fantom [35]2 years ago
4 0

Answer:

0.146 m

Explanation:

f = -KΔL according to Hooke's law

volume of water displaced = mass / density of block since a body will displace equal volume of its own

weight of water displaced = mass of water × acceleration due to gravity

and mass of water = volume of water / density of water

weight of water displaced = Vw × dw × g = mg (dw / dblock)

net force = mg - mg (dw / dblock) = 42.728  - 65.74 = -23.00

it will be balanced by a restoring force of 23 N

ΔL = F / k = 23 / 158 = 0.146 m

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The correct options are;

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4. Please see attached drawing for example

5. Please see attached drawing for example

6. The data points will fall along a line this that as the force increases, the acceleration increases

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A train engine pulling a boxcar what horizontal forces are;

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2. The vertical forces are the forces acting an  the direction of the y-axis of a graph

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Learn more here;;

brainly.com/question/19657850

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