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Ganezh [65]
3 years ago
6

The children at the local park think the slide is too slow. There is too much fiction. What could you do to decrease the amount

of friction on the slide?
Physics
1 answer:
igor_vitrenko [27]3 years ago
7 0
In order to decrease the friction on the slide,
we could try some of these:

-- Install a drippy pipe across the top that keeps continuously
dripping olive oil on the top end of the slide.  The oil oozes
down the slide and keeps the whole slide greased.

-- Hire a man to spread a coat of butter on the whole slide,
every 30 minutes.

-- Spray the whole slide with soapy sudsy water, every 30 minutes.

-- Drill a million holes in the slide,and pump high-pressure air
through the holes.  Make the slide like an air hockey table.

-- Keep the slide very cold, and keep spraying it with a fine mist
of water.  The water freezes, and a thin coating of ice stays on
the slide.

-- Ask a local auto mechanic to please, every time he changes
the oil in somebody's car, to keep all the old oil, and once a week
to bring his old oil to the park, to spread on the slide.  If it keeps
the inside of a hot car engine slippery, it should do a great job
keeping a simple park slide slippery.

-- Keep a thousand pairs of teflon pants near the bottom of the ladder
at the beginning of the slide.  Anybody who wants to slide faster can
borrow a set of teflon pants, put them on before he uses the slide, and
return them when he's ready to go home from the park.
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kotykmax [81]

The action-reaction pairs in the given situation are:

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  • the and and the wall

<h3>What are action-reaction pairs?</h3>

Action-reaction pairs are two forces which are equal but oppositely directed in their line of action.

Action-reaction pairs are according to Newton's third law of motion.

The action-reaction pairs in the given situation are:

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3 0
2 years ago
A solid uniform cylinder is rolling without slipping. What fraction of its kinetic energy is rotational?
tester [92]

Answer:

Explanation:

Let m be the mass of cylinder and r be the radius. It is moving with velocity v and angular velocity is ω. Let I be the moment of inertia of the cylinder.

I = 0.5 mr²

Total kinetic energy, T = 0.5 mv² + 0.5 Iω²

T = 0.5 (mv² + 0.5 mr²ω²)

v = rω

So, T = 0.5 (mv² + 0.5 mv²) = 0.75 mv²

Rotational kinetic energy is

R = 0.5 Iω² = 0.5 x 0.5 mr²ω²

R = 0.25 mv²

So, R / T = 0.25 / 0.75 = 1/3

5 0
3 years ago
Modern observations have shown that the geometry of the universe is ____.
lesantik [10]

Modern observations have shown that the geometry of the universe is flat and the universe mist be infinite.

<h3>What is geometry?</h3>

Geometry refer to a branch of mathematics that encapsulates measurements of lines, shapes, dimensions, points and shapes.

Therefore, Modern observations have shown that the geometry of the universe is flat and the universe mist be infinite.

Learn more about geometry below.

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8 0
2 years ago
What are the best units for DENSITY of a solid like a rock or a lemon? *
Ulleksa [173]
You would use answer 2O g/cm3
4 0
3 years ago
Work of 5 Joules is done in stretching a spring from its natural length to 19 cm beyond its natural length. What is the force (i
densk [106]

Answer:

Explanation:

Given that,

5J work is done by stretching a spring

e = 19cm = 0.19m

Assuming the spring is ideal, then we can apply Hooke's law

F = kx

To calculate k, we can apply the Workdone by a spring formula

W=∫F.dx

Since F=kx

W = ∫kx dx from x = 0 to x = 0.19

W = ½kx² from x = 0 to x = 0.19

W = ½k (0.19²-0²)

5 = ½k(0.0361-0)

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Then, k = 10/0.0361

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The spring constant is 277.008N/m

Then, applying Hooke's law to find the applied force

F = kx

F = 277.008 × 0.19

F = 52.63 N

The applied force is 52.63N

6 0
3 years ago
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