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Bess [88]
3 years ago
9

10) Donovan has $870.39 in his bank

Mathematics
2 answers:
timofeeve [1]3 years ago
7 0

Answer:770.64

Step-by-step explanation:

alexandr1967 [171]3 years ago
5 0
So to start:
870.39 + 50.25= $920.64
(Keyword: DEPOSIT) meaning ADD
Next:
920.64 - 150= $770.64
(Keyword: WITHDRAW) meaning SUBTRACT

Answer: $770.64

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A retailer incurs a fixed cost of N$ 500 when purchasing sugar for his stock. He pays N$ 10.00 per packet which he resells at N$
Arada [10]

Answer:

100 packets

Step-by-step explanation:

Given :

Cost = fixed cost + variable cost

Fixed cost = $500

Variable cost = $10

Sales price = $15

Let :

Number of packets = x

To break even :

fixed cost + variable cost = sales made

500 + 10x = 15x

500 = 15x - 10x

500 = 5x

x = 500 / 5

x = 100

100 packets

8 0
3 years ago
Need this asap pleaseeeee
Alex787 [66]

Answer:

615.6

Step-by-step explanation:

14 to the power of 2 is 196

196 multiplied by pi is 615.6

Hope this helps!

8 0
3 years ago
Tamar needs to make at least $84 at work on Tuesday to afford dinner and a movie on Wednesday night. She makes $14 an hour at he
Debora [2.8K]
6 hours because 14 times 6 is 84
4 0
4 years ago
The weight of 10 identical samples of a substance is 0.1 pound. what is the weight of 1000 samples
Irina-Kira [14]
The weight of 1000 samples is 10 pounds
8 0
3 years ago
Read 2 more answers
Suppose a company's revenue function is given by R(q) = - q^3 + 220q^2 and its cost function is given by C(q) = 500 + 13q, where
monitta

Answer:

A) MP(q) = -3q² + 440q - 13

B) 146.64 units.

Step-by-step explanation:

The profit function is given by the revenue minus the cost function:

P(q) = R(q) - C(q)\\P(q) = -q^3+220q^2-500-13q

A) The Marginal profit function is the derivate of the profit function as a function of the quantity sold:

P(q) = -q^3+220q^2-500-13q\\MP(q) = \frac{dP(q)}{dq} \\MP(q)=-3q^2+440q-13

B) The value of "q" for which the marginal profit function is zero is the number of items (in hundreds) that maximizes profit:

MP(q)=0=-3q^2+440q-13\\q=\frac{-440\pm \sqrt{440^2-(4*(-3)*(-13))} }{-6}\\q'=146.64\\q'' = - 0.03

Therefore, the only reasonable answer is that 146.64 hundred units must be sold in order to maximize profit.

4 0
3 years ago
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