Answer:2
Step-by-step explanation:
If a,b, and c are prime numbers, do (a*b) and c have a common factor that is greater than 1
(1) a,b, and c are all different prime numbers
(2) c≠2
1. Let's assume values of 1,3 and 5 to a, b, and c respectively
a b = 1*3 = 3
3 and 5 do not have any common factor aside 1
Let's assume values of 1,3 and 2 to a,b and c respectively
a *b = 1*3 = 3
3 and 2 does not have a common factor aside 1
2. c 
2
Let's assume values of 2,7 and 3 to a b and c response
a * b = 2 *7 = 14
14 and 3 does not have a common factor aside 1
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Answer:
a) 229 and 305 days
b) 229 days or less
c) 305 days or more
Step-by-step explanation:
The Empirical Rule(68-95-99.7 rule) states that, for a normally distributed random variable:
68% of the measures are within 1 standard deviation of the mean.
95% of the measures are within 2 standard deviation of the mean.
99.7% of the measures are within 3 standard deviations of the mean.
In this problem, we have that:
Mean = 267
Standard deviation = 19
(a) Between what values do the lengths of the middle 95% of all pregnancies fall?_____________and___________days
By the Empirical rule, 95% of all pregnancies fall within 2 standard deviations of the mean.
So
267 - 2*19 = 229 days
to
267 + 2*19 = 305 days
(b) How short are the shortest 2.5% of all pregnancies?______days or less
95% of all pregnancies fall within 2 standard deviations of the mean. The other 5% are more than 2 standard deviations from the mean. Since the distribution is symmetric, 2.5% is more than 2 standard deviations below the mean(shortest 2.5%) and 2.5% is more than 2 standard deviations above the mean(longest 2.5%). So
267 - 2*19 = 229 days
c) How long do the longest 2.5% of pregnancies last?________days or more
Explanation in b)
267 + 2*19 = 305 days
Answer:
Step-by-step explanation:
