Question

An empty 3.00 l bottle weighs 1.70 kg. filled with a certain wine, it weighs 4.72 kg. the wine contains 11.5% ethyl alcohol by mass. how many grams of ethyl alcohol are there in 250.0 ml of this wine?

Answer 1

Given:
m₁ = 1.70 kg, mass of the empty 3.00 L bottle
m₂ = 4.72 kg, the mass of the bottle and wine.

The mass of the wine is
m = m₂ - m₁ = 4.72 - 1.70 = 3.02 kg

Because the volume of the wine is 3.00 L, its density may be expressed as
(3.02 kg)/(3.00 L) = 1.0067 kg/L

The amount (density) of ethyl alcohol in the wine is
0.115*(1.0067 kg/L) = 0.1158 kg/L

In 250 mL of this wine, the mass of ethyl alcohol is
(250 x 10⁻³ L)*(0.1158 kg/L) = 0.02895 kg = 28.95 g

Answer:  28.95 g