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Dennis_Churaev [7]
2 years ago
9

Giving brainly if correct​

Chemistry
1 answer:
Nonamiya [84]2 years ago
7 0
The size of the container.
Think about if you were stirring sugar into your cup of tea - the size of the cup doesn’t matter, but the other stuff does.
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What happens when
jolli1 [7]

Answer:

a i think but idk

Explanation:

3 0
3 years ago
Assume that 1.0 mol of C4H10 is completely burned in excess oxygen to form carbon dioxide and water. How many moles of CO2 would
In-s [12.5K]
You need to first write a chemical equation and balance it
 C₄H₁₀ + O₂ → CO₂ + H₂O
2 C₄H₁₀ + 13 O₂ → 8 CO₂ + 10 H₂O
1.0 moles               X moles
1.0 mol C₄H₁₀ (\frac{8 mol CO₂}{2 mol C₄H₁₀}) = 4 moles of CO₂
7 0
3 years ago
In your chemistry class, your instructor fills three different flasks with three different gases. She tells you that one gas is
Digiron [165]

air in the first

oxygen in the second

CO2 in the third

6 0
2 years ago
Three test tubes contain white crystalline organic solids A, B, and C, each of which melts at 149-150 degrees C. A 50-50 mixture
Digiron [165]

Answer:

The mixture of B and C will melt as 130 - 139 ºC.

Explanation:

If the melting point (130 - 139 ºC) of a mixture of A and B is lower than the pure substances that is 149 - 150 ºC that means that one of these susbtances is an impurity because reduces the melting point.

If the melting point of the mixture of A and C is the same as the pure substances, we can deduce that they are the same substances, also because the melting point when a substance is pure is just 1 or 2 ºC like in this case.

So in a Mixture of B and C is going to be like the first case of the mixture among A and B, because the B substance is the impurity.

3 0
3 years ago
What is the charge of phosphate in AlPO4?
Dennis_Churaev [7]

The charge of phosphate : 3-

<h3>Further explanation</h3>

Oxidation is an increase in oxidation number, while reduction is a reduction in oxidation number.

The formula for determining Oxidation Numbers in general:

1. Single element atomic oxidation number = 0.

Group IA (Li, Na, K, Rb, Cs, and Fr): +1

Group IIA (Be, Mg, Ca, Sr and Ba): +2

Group IIIA(Al, B) : +3

H in compound = +1, except metal hydride compounds (Hydrogen which binds to groups IA or IIA) oxidation number H = -1, for example, LiH, MgH₂, etc.

2. Oxidation number O in compound = -2, except OF2 = + 2 and in peroxide (Na₂O₂, BaO₂) = -1 and superoxide, for example KO₂ = -1/2.

3 The oxidation number in an uncharged compound = 0,

Total oxidation number in ion = ion charge, Example NO₃⁻ = -1

Compound AlPO₄ :

The oxidation number in an uncharged compound = 0

Since the charge of Al as group 3A (or group 13) is +3, while the AlPO₄ compound is a polyatomic compound (consisting of polyatomic ions PO₄ and Al), the PO₄ charge:

charge Al + charge PO₄ = 0

+ 3 + charge PO₄ = 0

<em>charge PO₄ = -3</em>

6 0
2 years ago
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