solution:
the change in the boiling point is given as,
dTbp =2.30°c
elevation constant for the solvent is given by,
kb=0.512°c/m
= 4.49m
Answer:
178.98 sq. feet
Explanation:
The path and the garden has been shown in the figure below. The green area is the garden and the area in brown is the path.
It has been given that,
Radius of garden = 8 feet
So, the area of garden = 3.14 × 8 × 8 = 200.96 sq. feet
The total radius of the land including garden and path = 8 + 3 = 11 feet
So, the total are of land including garden and path = 3.14 × 11 × 11 = 379.94 sq. feet
So, the area of path = Total area of the land - area of garden
Area of path = 379.94 - 200.96 = 178.98 sq. feet
The answer is Thickness of solution.
The Beer-Lambert Law equation has the following form:
A=E×b×c
Where A is absorbance, E <span>is the molar absorbtivity, </span>b is the path length of the sample and c <span>is the concentration of the compound in solution.
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<span>Lamber-Ber's law shows that the absorbance of a solution is directly proportional to the concentration of the species to be absorbed, as well as the length of the path. For example, if the length of the path is constant, the UV / VIS spectroscopy can be used to determine the concentration of the absorbent substance in the solution.</span>
1.34 grams of MgNH4PO4*6H2O
Molar mass= 245.1 grams per mole
Moles of MgNH4PO4*6H2O=
(1.34 grams)(1 mole/245.1 grams fertilizer)=0.0054671563 moles fertilizer
MgNH4PO4*6H2O has 1 mole of Phosphorous, so:
0.0054671563 moles fertilizer(1 mole Phosphorous/1 mole fertilizer)
0.0054671563 moles Phosphorous (30.97 grams/ 1 mole)
=0.1693178295 grams Phosphorous
<span>Answer – We are given, 2H2+O2 ----> 2H2O , deltaH = -48.4 kJ Moles of H2 =1.8 moles From the above given balanced equation We know, 2 moles of H2 = -48.4 kJ So, 1.8 moles of H2 = ? kJ = 1.8 moles of H2 X -48.4 kJ / 2 moles of H2 =-43.6 kJ So, when 1.8 mol of H2...</span>
