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vaieri [72.5K]
2 years ago
15

The directness of the sunlight at a specific latitude will determine the amount of solar energy that latitude receives. Please s

elect the best answer from the choices provided T F
Chemistry
1 answer:
frez [133]2 years ago
4 0

Answer:

True

Explanation:

The amount of solar energy a particular place receives is directly dependent on the directness of the sunlight. This is like this because the more direct the sunlight is , the more concentrated at smaller area it is, thus warming the area more, and the less direct the sunlight is, the more dispersed the sunlight is, and the area is heated much less. The directness of the sunlight depends on the inclination of the Earth, as well as the shape of the Earth. The inclination makes certain areas be more exposed to the sunlight in part of the year, and than be less exposed in the other part of the year. The shape of the Earth is directly influencing the angle by which the sunlight falls, the lower the latitude, the more direct the sunlight, the higher the latitude, the less direct the sunlight.

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Percentage yield of sodium peroxide if 5 g of sodium oxide produces 5.5 g of sodium peroxide
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<h3>Answer:</h3>

87.40 %

<h3>Explanation:</h3>

Concept being tested: Percent yield of a product

We are given;

Mass of Sodium oxide 5 g

Experimental or Actual yield of sodium peroxide IS 5.5 g

We are required to calculate the percent yield of sodium peroxide;

The equation for the reaction that forms sodium peroxide is

2Na₂O + O₂ → 2Na₂O₂

<h3>Step 1; moles of sodium oxide</h3>

Moles = mass ÷ molar mass

Molar mass of sodium oxide is 61.98 g/mol

Therefore;

Moles = 5 g ÷ 61.98 g/mol

          = 0.0807 moles

<h3>Step 2: Theoretical moles of sodium peroxide produced </h3>

From the equation, 2 moles of sodium oxide produces 1 mole of sodium peroxide.

Thus, moles of sodium peroxide used is 0.0807 moles

<h3>Step 3: Theoretical mass of sodium peroxide used</h3>

Mass = Number of moles × Molar mass

Molar mass of sodium peroxide = 77.98 g/mol

Therefore;

Theoretical mass = 0.0807 moles × 77.98 g/mol

                            = 6.293 g

Theoretical mass of Na₂O₂ is 6.293 g

<h3>Step 4: Percent yield of Na₂O₂</h3>
  • We know that percent yield is given by the ratio of actual yield to theoretical yield expressed as a percentage.

Percent yield=(\frac{Actual yield}{theoretical yield})100

Percent yield(Na_{2}O_{2})=(\frac{5.5g}{6.293g})100

                       = 87.40 %

Therefore, the percentage yield of sodium peroxide is 87.4%

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