A 0.66... that the repeating decimals
Answer:
the answer is -5< x
Step-by-step explanation:
you you start by subtracting 7 by both sides leaving you with -20<4x. then then divide both sides by 4 leaving you with -5< x
<span>What is the expression using GCF of 2+8
= 2(1+4)
= 2(5)
=10</span>
Answer:
![P(X \geq0.55) \leq 0.22](https://tex.z-dn.net/?f=P%28X%20%5Cgeq0.55%29%20%5Cleq%200.22)
Step-by-step explanation:
Using central Limit Theorem (CLT), The sum of 100 random variables;
is approximately normally distributed with
Y ~ N (100 ×
) = N ( 50,
)
The approximate probability that it will take this child over 55 seconds to complete spinning can be determined as follows;
N ( 50,
)
![P(Y>55) =P(Z>\frac{55-50}{10/3})](https://tex.z-dn.net/?f=P%28Y%3E55%29%20%3DP%28Z%3E%5Cfrac%7B55-50%7D%7B10%2F3%7D%29)
![P(Y>55) =P(Z>1.5)](https://tex.z-dn.net/?f=P%28Y%3E55%29%20%3DP%28Z%3E1.5%29)
![P(Y>55) =\phi (-1.5)](https://tex.z-dn.net/?f=P%28Y%3E55%29%20%3D%5Cphi%20%28-1.5%29)
![P(Y>55) =0.0668](https://tex.z-dn.net/?f=P%28Y%3E55%29%20%3D0.0668)
Using Chebyshev's inequality:
![P(|X-\mu\geq K)\leq \frac{\sigma^2}{K^2}](https://tex.z-dn.net/?f=P%28%7CX-%5Cmu%5Cgeq%20K%29%5Cleq%20%5Cfrac%7B%5Csigma%5E2%7D%7BK%5E2%7D)
Let assume that X has a symmetric distribution:
Then:
![2P(X-\mu\geq K)\leq) \frac{\sigma^2}{K^2}](https://tex.z-dn.net/?f=2P%28X-%5Cmu%5Cgeq%20K%29%5Cleq%29%20%5Cfrac%7B%5Csigma%5E2%7D%7BK%5E2%7D)
![2P(X \geq \mu+K)\leq) \frac{\sigma^2}{K^2}](https://tex.z-dn.net/?f=2P%28X%20%5Cgeq%20%5Cmu%2BK%29%5Cleq%29%20%5Cfrac%7B%5Csigma%5E2%7D%7BK%5E2%7D)
where: (
)
![P(X \geq0.55) \leq 0.22](https://tex.z-dn.net/?f=P%28X%20%5Cgeq0.55%29%20%5Cleq%200.22)
Answer:
Exponential
Step-by-step explanation:
I have worked with this functions before.