Since the spinner is labelled A, B, C, D, there are four possible landing for the spinner.
Thus, the sample space is {A, B, C,D}.
Therefore, the number of <span>elements in the sample space for spinning a spinner labeled A, B, C, D</span> is 4.
Answer:
-2
Step-by-step explanation:
Answer:
0.2287
Step-by-step explanation:
The computation of the probability that the automated manufacturing system runs for more than 18 hours without a failure is shown below:
P(X > 17) = 1 - P(X < 17)
= 1 - [1 - e^-18 ÷ 12.2]]
= 1 - [1 -0.228684984
]
= 0.2287
Answer:
x=-7,1
Step-by-step explanation: