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Aleksandr-060686 [28]
3 years ago
11

Select all of the expressions that are equal to 6

Mathematics
1 answer:
Ivan3 years ago
8 0
Add the possible answers so we know all options
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If h(x) = 5 x and k(x)=1/x, which expression is equivalent to (koh)(x)?
Anestetic [448]
(k\circ h)(x)=k(h(x))

\displaystyle k(h(x))= \frac{1}{h(x)}=  \frac{1}{5x}
6 0
3 years ago
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What is the approximate area of the circle?
Sophie [7]

Answer:

B

Step-by-step explanation:

because it is

5 0
2 years ago
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Can someone explain how to do #3?
dsp73

\displaysyle (\sqrt 2)^{3}=(2^{\frac{1}{2}})^3=2^{\frac{1}{2} \cdot 3}=2^{\frac{3}{2}}=\sqrt {2^3}=\sqrt 8

√8 is between 2 and 3, because 2²=4<8, but 3²=9>8. Also, our value is closer to 3 than to 2, so it is more than 2.5 and we have C and D options left.

Among these two numbers we find the one which is closer to √8.

C. 27=√729 ⇒ 2.7=√7.29

D. 28=√784 ⇒ <u>2.8=√7.84</u>

Hence our answer is D) 2.8

5 0
3 years ago
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According to the info in the table, who is the fastest typist?
Anastaziya [24]

Answer:

shaquille

Step-by-step explanation:

she had the greatest rate of typing

8 0
2 years ago
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Find an equation, or a set of equations, to describe the set of points that are equidistant from the points p(−9, 0, 0) and q(3,
wariber [46]
X = -3.  
The distance from p(-9, 0, 0) is
 d = sqrt((x+9)^2 + y^2 + z^2) 
 The distance from q(3,0,0) is
 d = sqrt((x-3)^2 + y^2 + z^2) 
 Let's set them equal to each other.
 sqrt((x+9)^2 + y^2 + z^2) = sqrt((x-3)^2 + y^2 + z^2)
  Square both sides, then simplify
 (x+9)^2 + y^2 + z^2 = (x-3)^2 + y^2 + z^2
 x^2 + 18x + 81 + y^2 + z^2 = x^2 - 6x + 9 + y^2 + z^2
 18x + 81 = - 6x + 9
 24x + 81 = 9
 24x = -72
 x = -3 
 So the desired equation is x = -3 which defines a plane.
7 0
3 years ago
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