Answer is: 0,453 <span> moles of oxygen will react </span><span>with 0.3020 moles of carbon(IV) oxide</span><span>.
</span>n(CO₂) = 0,302 mol.
From chemical reaction: n(CO₂) : n(O₂) = 4 : 6.
n(O₂) = 6 · 0,302 mol ÷ 4.
n(O₂) = 0,453 mol.
n - amount of substance.
Answer:
607 ppm
Explanation:
In this case we can start with the <u>ppm formula</u>:

If we have a solution of <u>0.0320 M</u>, we can say that in 1 L we have 0.032 mol of
, because the molarity formula is:

In other words:


If we use the <u>atomic mass</u> of
(19 g/mol) we can convert from mol to g:
Now we can <u>convert from g to mg</u> (1 g= 1000 mg), so:

Finally we can <u>divide by 1 L</u> to find the ppm:

<u>We will have a concentration of 607 ppm.</u>
I hope it helps!
Answer:
New volume = 150 mL
Explanation:
Initial temperature, T₁ = 35°C
Initial volume, V₁ = 350 mL
We need to find the change in volume when the temperature drops to 15°C.
The relation between the temperature and the volume is given by Charle's law. Let new volume is V₂. It can be given by :

So, the new volume is 150 mL.
<span>Ka is an equilibrium constant for the partial ionization of "weak" acids in water.</span>