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3 years ago

I need an answer asap thank you all for your answers! xoxo, anastasia

Chemistry

1 answer:

ICE Princess25 [194]3 years ago

5 0

The answer is b because it could happen to you

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What is the difference between diffusion and osmoses<br><br>

Citrus2011 [14]

Answer:

Diffusion means that particles travel from a higher concentration to a lower concentration region before balance is achieved. The semi-permeable membrane is present in osmosis, so that only solvent molecules can travel freely to equalize the levels.

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3 years ago

Complete the sentence. The higher the hydrogen ion concentration, the ______ the pH.

arsen [322]

The answer would be lower because the higher the pH is he lower the number is

7 0

3 years ago

Read 2 more answers

A mysterious white powder could be powdered sugar (C12H22O11), cocaine (C17H21NO4), codeine (C18H21NO3), norfenefrine (C8H11NO2)

konstantin123 [22]

Answer: norfenefrine $(C_8H_{11}NO_2)$

Explanation:

Depression in freezing point is given by:

$\Delta T_f=i\times K_f\times m$

$\Delta T_f=T_f^0-T_f=(-114.6-(-115.5)^0C=0.9^0C$ = Depression in freezing point

i= vant hoff factor = 1 (for non electrolyte)

$K_f$ = freezing point constant = $1.99^0C/m$

m= molality

$\Delta T_f=i\times K_f\times \frac{\text{mass of solute}}{\text{molar mass of solute}}\times \text{weight of solvent in kg}}$

Weight of solvent (ethanol)= $density\times volume=0.789g/cm^3\times 1.50cm^3=1.18g=1.18\times 10^{-3}kg$

Molar mass of unknown non electrolyte = M g/mol

Mass of unknown non electrolyte added = 82 mg = 0.082 g (1g=1000mg)

$0.9=1\times 1.99\times \frac{0.082g}{M g/mol\times 1.18\times 10^{-3}}kg}$

$M=154g/mol$

The molecular mass of norfenefrine $(C_8H_{11}NO_2)$ is near to 154 and thus the identity of the white powder is norfenefrine .

4 0

3 years ago

What is the molarity (M) of an 85.0-mL solution (total volume) containing 1.77 g of ethanol (C2H5OH)

Liono4ka [1.6K]

Answer: The molarity of solution is 0.453 M

Explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.

$Molarity=\frac{n\times 1000}{V_s}$

where,

n = moles of solute

$V_s$ = volume of solution in ml

moles of $C_2H_5OH$ = $\frac{\text {given mass}}{\text {Molar mass}}=\frac{1.77g}{46g/mol}=0.0385mol$

Now put all the given values in the formula of molality, we get

$Molarity=\frac{0.0385\times 1000}{85.0}$

$Molarity=0.453$

Therefore, the molarity of solution is 0.453 M

7 0

3 years ago

What is the ph of a 0.15 m solution of ammonium bromide?

pochemuha

NH3 + H20 YIELDS NH4+ + OH-

So, the NH3 and the OH- are stoichiometrically equivalent.

So, we have 0.15M OH-

p OH = -log [OH-]

p OH = -log[0.15) = 0.824

pH = 14 - p OH

pH = 13.18

5 0

3 years ago