Answer:
Hello There!!
Explanation:
C. a color change
Colour is not an indicator. Sorry if I'm wrong.
hope this helps,have a great day!!
~Pinky~
The variable we have to determine for this problem is the time. Since the given information is speed, we have to know the distance so that we can solve for the time. From literature, the distance between the Earth and the moon is 384,400,000 meters. Therefore,
Speed = Distance/Time
Time = Distance/Speed
Time = 384,400,000 m/ 3×10⁸ m/s = 1.28 seconds
Answer:
When the pressure increases to 2.35 atm, the temperature will increase to 378 K
Explanation:
Step 1: Data given
The initial pressure = 1.82 atm
The initial temperature = 293 K
The pressure will be increased to 2.35 atm
Step 2: Calculate the new temperature
P1/T1 = P2/T2
⇒with P1 = the initial pressure = 1.82 atm
⇒with T1 = the initial temperature = 293 K
⇒with P2 = the increased pressure = 2.35 atm
⇒with T2 = the new temperature = TO BE DETERMINED
1.82atm / 293 K = 2.35 atm / T2
T2 = 2.35 atm / (1.82 atm/293 K)
T2 = 2.35 / 0.0062116
T2 = 378 K
When the pressure increases to 2.35 atm, the temperature will increase to 378 K
Answer:
The answer to your question is:
Explanation:
Data
moles H=?
moles of N = 0.0969
moles of NH₃=?
N₂ (g) + 3 H₂ (g) ⇒ 2NH₃ (g)
Process
1.- Set a rule of three to calculate the moles of hydrogen
1 mol of nitrogen ------------- 3 moles of hydrogen
0.0969 moles of N ---------- x
x = (0.0969 x 3) / 1
x = 0.2907 moles of hydrogen
2.- Set a rule of three to calculate the moles of ammonia
1 mol of nitrogen -------------- 2 moles of ammonia
0.0969 mol of N -------------- x
x = (0.0969 x 2) / 1
x = 0.1938 moles of ammonia
Answer:
351.43mL
Explanation:
To calculate the original volume of hydrogen gas in this question, the Boyle's law equation will be used. Boyle's law equation is:
P1V1 = P2V2
Where; P1 = initial pressure
V1 = initial volume
P2 = final pressure
V2 = final volume
According to this question, the P1= 1.56atm, V1 = ?, P2 = 0.73atm, V2 = 751mL
Hence;
P1V1 = P2V2
1.56 × V1 = 0.73 × 751
1.56 V1 = 548.23
V1 = 548.23/1.56
V1 = 351.43mL
Therefore, the original volume of hydrogen gas is 351.43 mL.
