All categories

2 years ago

If I dilute 334.75 mL of 1.28 M lithium acetate solution to a volume of 822.18 ml, what

Chemistry

1 answer:

zlopas [31]2 years ago

3 0

Answer:

C₂ = 0.52 M

Explanation:

Given data:

Initial volume = 334.75 mL

Initial concentration = 1.28 M

Final volume = 822.18 mL

Final concentration = ?

Solution:

C₁V ₁ = C₂V₂

By putting values,

1.28 M×334.75 mL = C₂×822.18 mL

C₂ = 1.28 M×334.75 mL / 822.18 mL

C₂ = 428.48 M.mL / 822.18 mL

C₂ = 0.52 M

You might be interested in

What is the atomic mass equal to?

mixer [17]

Atomic mass is equal to the total number of electrons neutrons and protons

8 0

3 years ago

Read 2 more answers

Facial dimples in man are dominatant over no dimples. Show

Nat2105 [25]

I'm assuming false but really have no clue

3 0

3 years ago

Dr. House took two liquids of different densities (p_1=1500 kg/m^3; p_2 = 500 kg/m^3) are poured together into a 0.1 m^3 tank fi

SVETLANKA909090 [29]

We know that:
mass = density x volume
The volume of the total mixture is 0.1 m³
Let the first liquid be A and the second be B
Mass Total = Mass A + Mass B

800 x 0.1 = 1500Va + 500(0.1 - Va)
30 = 1000Va
Va = 0.03 m³
Vb = 0.1 - 0.03 = 0.07 m³

6 0

3 years ago

How does a screw make the work of fastening two objects together easier? A. The screw changes the direction of a force - it conv

Pachacha [2.7K]

<span>D. The screw changes the direction of a force - it converts linear force into rotational force. It also reduces the force required - the closer the threads, the smaller the input force required to get the same output force.</span>

3 0

3 years ago

Read 2 more answers

The half life for the decay of carbon- is years. Suppose the activity due to the radioactive decay of the carbon- in a tiny samp

EleoNora [17]

The question is incomplete. The complete question is:

The half-life for the decay of carbon-14 is 5.73x10^3 years. Suppose the activity due to the radioactive decay of the carbon-14 in a tiny sample of an artifact made of woodfrom an archeological dig is measured to be 2.8x10^3 Bq. The activity in a similiar-sized sample of fresh wood is measured to be 3.0x10^3 Bq. Calculate the age of the artifact. Round your answer to 2 significant digits.

Answer:

570 years

Explanation:

The activity of the fresh sample is taken as the initial activity of the wood sample while the activity measured at a time t is the present activity of the wood artifact. The time taken for the wood to attain its current activity can be calculated from the formula shown in the image attached. The activity at a time t must always be less than the activity of a fresh wood sample. Detailed solution is found in the image attached.

6 0

3 years ago