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Grace [21]
3 years ago
10

Which phase change is the opposite of boiling?

Chemistry
1 answer:
Yuri [45]3 years ago
8 0

Answer:

Condensing (I think is what you are looking for)

Explanation:

Boiling is liquid -> gas

Condensing is gas -> liquid

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4 0
3 years ago
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You have 50 ml of a complex mixture of weak acids that contains some HF (pKa = 3.18) and some HCN (pKa = 9.21). Which is larger,
telo118 [61]

Answer:

\frac{[F^{-}]}{[HF]} is larger

Explanation:

pK_{a}=-logK_{a} , where K_{a} is the acid dissociation constant.

For a monoprotic acid e.g. HA, K_{a}=\frac{[H^{+}][A^{-}]}{[HA]} and \frac{[A^{-}]}{[HA]}=\frac{K_{a}}{[H^{+}]}

So, clearly, higher the K_{a} value , lower will the the pK_{a}

In this mixture, at equilibrium, [H^{+}] will be constant.

K_{a} of HF is grater than K_{a} of HCN

Hence, (\frac{F^{-}}{[HF]}=\frac{K_{a}(HF)}{[H^{+}]})>(\frac{CN^{-}}{[HCN]}=\frac{K_{a}(HCN)}{[H^{+}]})

So, \frac{[F^{-}]}{[HF]} is larger

8 0
4 years ago
Have some points chemistry gang RISE UP
densk [106]

Answer:

I WILL ACHIEVE GREATNESS

Explanation:

7 0
3 years ago
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How do balanced chemical equations show the conservation of mass?
stepladder [879]

You cannot create something from nothing and similarly you cannot create less from more, if you didn't balance an equation that needs to be balanced, your product might end up equalling more or less than the total mass of the two elements combined. Which is impossible

3 0
4 years ago
What is the half-life of an isotope that decays to 12.5% of its original activity in 19.8 hours?
katen-ka-za [31]
x= x_{0}  e^{kt} ,where~ x ~is~ the ~ |amount\ of \material\ at\ any~~time~t

and~ x_{0} ~the~original~amount.
when~x=  \frac{12.5}{100} x_{0}  }= \frac{125}{1000}  x_{0}
\frac{x}{ x_{0} } = \frac{125}{1000}= \frac{1}{8}
when t=19.8 hrs,
x= x_{0}  e^{19.8 k}, 
 \frac{x}{ x_{0} } = e^{19.8 k}, 
 \frac{1}{8} = e^{19.8k} ,
ln \frac{1}{8} =19.8 k,

ln1-ln8=19.8k,
0-ln 2^{3} =19.8 k,
-3 ln2=19.8k
k= \frac{-3 ln2}{19.8} = \frac{- ln 2}{6.6}x= x_{0}  e^{ \frac{-ln2}{6.6}t } ,
 \frac{x}{ x_{0} } = e^{ \frac{- ln 2}{6.6}t } 
\frac{1}{2} = e^{ \frac{- ln2}{6.6}t } = \frac{1}{ e^{ \frac{ln 2}{6.6} t} } ,
2= e^{ \frac{ln2}{6.6}t } ,
ln2=ln  e^{ \frac{ln 2}{6.6}t } = \frac{ln 2}{6.6} t~ln e= \frac{ln2}{6.6} t,
8 0
4 years ago
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