How do I solve the equation; 6(x^2-2)=12
1 answer:
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1. x = 3, y = 2
2. x = -99/68, y = -14/17
3. x = -4, y = 1
4. x = 1, y = 5
5. x = -1, y = 0
6. x = 2, y = -3
7. x = 14, y = 20
I attached the pictures with the work.
2. x = -99/68, y = -14/17
3. x = -4, y = 1
4. x = 1, y = 5
5. x = -1, y = 0
6. x = 2, y = -3
7. x = 14, y = 20
I attached the pictures with the work.
Answer: Anything that is 1202 or larger
In other words,
So we could have m = 1202, or m = 1203, or m = 1204, etc.
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Explanation:
- m = number of minutes used
- 0.07m = amount charged for those minutes used excluding the $25
- 0.07m+25 = total monthly bill now including the extra $25 fee
The monthly bill is at least $109.14, since this is the lowest amount she has been charged.
This says that the least number of minutes Martina has used is 1202 minutes.
So if m was a whole number, then m could be selected from the set {1202, 1203, 1204, ...}
Side note: 1202 minutes = 1202/60 = 20.033 hours approximately.
The slope of the given line is ∆y/∆x = (4-6)/(5-1) = -2/4 = -1/2. The slope of the desired (perpendicular) line is the negative reciprocal of this, -1/(-1/2) = 2.
The point-slope form of the equation for a line with slope m through point (h, k) is
... y - k = m(x - h)
For slope 2 and the given point, your equation can be
... y + 6 = 2(x + 2)
