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julia-pushkina [17]
3 years ago
13

What is the relative frequency of adults with tickets?

Mathematics
1 answer:
galben [10]3 years ago
4 0
a) 0.34

Hope I helped! ( Smiles )
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The LA Dodgers hit the most homeruns in 2014. The number of homeruns accounted for 6% of the entire major League baseball homeru
disa [49]

Answer:

35 homeruns

Step-by-step explanation:

583*0.06=349.8-->34.98-->35

8 0
3 years ago
Read 2 more answers
A student's grade depends on her score on four equally-weighted exams. Her average on the first three exams is 92. What must she
Sergeeva-Olga [200]
3x92 = 276 (first 3 exams)
average of at least 90 (90 x 4 = 360)

360 - 276 = 84

Answer
<span>she needs to score at least 84 on the fourth exam </span><span>in order to guarantee a final average of at least 90</span>
4 0
3 years ago
Reasoning in a laboratory, the probability a bacterial colony thrives is 70%. The numbers 0 to 6 represent the outcome that a co
Maurinko [17]

Answer:

The probability that exactly half of the colonies will thrive = (1/3) = 0.3333

Step-by-step explanation:

The list of random numbers simulates the out comes of 4 colonies.

Based On the simulation in 6 trails, what is the probability that exactly half of the colonies will thrive?

The probability of an event is given mathematically as the number of elements in the event divided the total number of elements in the sample space.

Noting that the numbers 0 to 6 indicate that a colony thrives and the number 7 to 9 represent that a colony doesn't thrive.

The 6 trials are given as

4285; 3 colonies thrive, 1 doesn't.

6903; 3 colonies thrive, 1 doesn't.

3829; 2 colonies thrive, 2 don't.

7871; 1 colony thrives, 3 don't.

2868; 2 colonies thrive, 2 don't.

5137; 3 colonies thrive, 1 doesn't.

The number of trials where exactly 2 colonies thrive = 2

The total number of trials = 6

The probability that exactly half of the colonies will thrive = (2/6) = (1/3) = 0.3333

Hope this Helps!!!

3 0
3 years ago
Verify tan(α+β) = [tan(α)+tan(β)] / [1 + tan(α)tan(β)]
mr Goodwill [35]

Answer:

Proved

Step-by-step explanation:

To Prove: tan(\alpha+\beta) =\dfrac{tan(\alpha)+tan(\beta)}{1 + tan(\alpha)tan(\beta)}

Proof:

Now: tan \theta =\dfrac{sin\theta }{cos \theta}

Therefore:

tan (\alpha+\beta)=\dfrac{ sin (\alpha+\beta)}{cos (\alpha+\beta) }

Applying these angle sum formula

sin (\alpha+\beta)=sin \alpha cos \alpha + sin \beta cos \beta\\cos (\alpha+\beta)=cos \alpha cos \beta - sin \alpha sin \beta

tan (\alpha+\beta)=\dfrac{ sin \alpha cos \alpha + sin \beta cos \beta}{cos \alpha cos \beta - sin \alpha sin \beta }

Divide all through by cos \alpha cos \beta

tan (\alpha+\beta)=\dfrac{ (sin \alpha cos \alpha)/(cos \alpha cos \beta) + (sin \beta cos \beta)/(cos \alpha cos \beta)}{(cos \alpha cos \beta)/(cos \alpha cos \beta) - (sin \alpha sin \beta)/(cos \alpha cos \beta) }\\\\tan (\alpha+\beta)=\dfrac{\frac{sin \alpha}{cos \alpha}+\frac{sin \beta}{cos \beta} }{1-tan \alpha tan \beta} \\$Therefore:\\\\tan (\alpha+\beta)=\dfrac{tan \alpha+tan \beta}{1-tan \alpha tan \beta}

=sin \alpha cos \beta + cos \alpha sin \beta/cos \alpha cos \beta/cos \alpha cos \beta- sin \alpha sin \beta/cos \alpha cos \beta  

=sin \alpha/cos \alpha + sin \beta/cos \beta/1-tan \alpha tan \beta  

=tan A + tan B/1-tan A tan B

5 0
4 years ago
Solve for x.<br> * X=28<br> x= 1<br> (Type an integer or a simplified fraction.)
marin [14]
The answer to that is 6/17
4 0
3 years ago
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