![\stackrel{\textit{\LARGE Line A}}{(\stackrel{x_1}{-8}~,~\stackrel{y_1}{5})\qquad (\stackrel{x_2}{-5}~,~\stackrel{y_2}{4})} ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{4}-\stackrel{y1}{5}}}{\underset{run} {\underset{x_2}{-5}-\underset{x_1}{(-8)}}} \implies \cfrac{4 -5}{-5 +8}\implies -\cfrac{1}{3} \\\\[-0.35em] ~\dotfill](https://tex.z-dn.net/?f=%5Cstackrel%7B%5Ctextit%7B%5CLARGE%20Line%20A%7D%7D%7B%28%5Cstackrel%7Bx_1%7D%7B-8%7D~%2C~%5Cstackrel%7By_1%7D%7B5%7D%29%5Cqquad%20%28%5Cstackrel%7Bx_2%7D%7B-5%7D~%2C~%5Cstackrel%7By_2%7D%7B4%7D%29%7D%20~%5Chfill%20%5Cstackrel%7Bslope%7D%7Bm%7D%5Cimplies%20%5Ccfrac%7B%5Cstackrel%7Brise%7D%20%7B%5Cstackrel%7By_2%7D%7B4%7D-%5Cstackrel%7By1%7D%7B5%7D%7D%7D%7B%5Cunderset%7Brun%7D%20%7B%5Cunderset%7Bx_2%7D%7B-5%7D-%5Cunderset%7Bx_1%7D%7B%28-8%29%7D%7D%7D%20%5Cimplies%20%5Ccfrac%7B4%20-5%7D%7B-5%20%2B8%7D%5Cimplies%20-%5Ccfrac%7B1%7D%7B3%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill)
keeping in mind that perpendicular lines have negative reciprocal slopes, and that parallel lines have equal slopes, well, those two slopes above aren't either, so since they're neither, and they're different, that means that lines A and B intersect.
Answer:
Yes, is a right triangle
Step-by-step explanation:
To know if you can build a right triangle with those sides we have to make the following equality
h² = l1² + l2²
The hypotenuse is always the longest side so it should be 39
we check the equality of the equation
39² = 15² + 36²
1521 = 225 + 1296
1521 = 1521
Equality was fulfilled so it is a right triangle
Answer:
Its the first one Guys
Step-by-step explanation:
I hope that helped :)
The second and the third one because first is the same as 3 4/7 and 81=3^4
Answer:
1.66 pounds
Step-by-step explanation:
4.98 dollars divided by 3 pounds
