All categories

3 years ago

Twice the difference of a number and 3 is at most 27

Mathematics

1 answer:

kozerog [31]3 years ago

6 0

Twice the difference of a number and 3 is at most 27

2*(n-3) <=27

to solve

distribute

2n -6 <=27

add 6 to each side

2n <=33

divide by 2

n <=33/2

n<= 16 1/2

You might be interested in

If your credit card is stolen and the thief runs up a total debt of $1,000, but you notify the issuer of the card as soon as you

Yuki888 [10]

Answer:

50 dollars

Step-by-step explanation:

college website

3 0

2 years ago

Reduce improper 24/5

iogann1982 [59]

The answer is 4 4/5

6 0

3 years ago

Arrange these functions from the greatest to the least value based on the average rate of change in the specified interval.

Romashka [77]

By definition, the average change of rate is given by:
$AVR = \frac{f(x2)-f(x1)}{x2-x1}$
We will calculate AVR for each of the functions.
We have then:

f(x) = x^2 + 3x interval: [-2, 3]:
$f(-2) = x^2 + 3x = (-2)^2 + 3(-2) = 4 - 6 = -2

f(3) = x^2 + 3x = (3)^2 + 3(3) = 9 + 9 = 18$
$AVR = \frac{-2-18}{-2-3}$
$AVR = \frac{-20}{-5}$
$AVR = 4$

f(x) = 3x - 8 interval: [4, 5]:
$f(4) = 3(4) - 8 = 12 - 8 = 4 f(5) = 3(5) - 8 = 15 - 8 = 7$
$AVR = \frac{7-4}{5-4}$
$AVR = \frac{3}{1}$
$AVR = 3$

f(x) = x^2 - 2x interval: [-3, 4]
$f(-3) = (-3)^2 - 2(-3) = 9 + 6 = 15

f(4) = (4)^2 - 2(4) = 16 - 8 = 8$
$AVR = \frac{8-15}{4+3}$
$AVR = \frac{-7}{7}$
$AVR = -1$

f(x) = x^2 - 5 interval: [-1, 1]
$f(-1) = (-1)^2 - 5 = 1 - 5 = -4

f(1) = (1)^2 - 5 = 1 - 5 = -4$
$AVR = \frac{-4+4}{1+1}$
$AVR = \frac{0}{2}$
$AVR = 0$

Answer:
these functions from the greatest to the least value based on the average rate of change are:
f(x) = x^2 + 3x
f(x) = 3x - 8
f(x) = x^2 - 5
f(x) = x^2 - 2x

5 0

3 years ago

what is the value of x in the diagram. if necessary round your answer to the nearest tenth of a unit

arlik [135]

Answer:

6.5

Step-by-step explanation:

4 0

2 years ago

What is the value of X?<br><br> Enter your answer in the box.

morpeh [17]