Answer:
x=3, y=1. (3, 1).
Step-by-step explanation:
x+3y=6
4x-6y=6
------------
simplify 4x-6y=6 into 2x-3y=3
------------------------
x+3y=6
2x-3y=3
--------------
3x=9
x=9/3
x=3
3+3y=6
3y=6-3
3y=3
y=3/3
y=1
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Answer:
- 3n+6 (n = smallest)
- 3n (n = middle)
Step-by-step explanation:
The usual method for doing this is to let n represent the smallest one. Then the three integers are ...
n, n+2, and n+4
and their sum is ...
(n) +(n+2) +(n+4) = 3n+6 . . . . sum of 3 consecutive odd integers (n = smallest)
_____
Personally, for consecutive number problems, I prefer to let the variable represent the average value. If n is the average value of 3 consecutive odd integers, is is the middle integer. Of course, the sum will be 3 times the average:
(n-2) +(n) +(n+2) = 3n . . . . sum of 3 consecutive odd integers (n = middle one)
Answer:
The answer you want is indeed, (C).
8.04
ED2021
