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lora16 [44]
3 years ago
8

Which of the following are part of kinetic-molecular theory? Check all that apply. The particles in a solid do not move. The par

ticles in a liquid are moving past one another constantly. The particles in gas move freely in all directions. The particles in a solid vibrate in a fixed position. The particles in a solid are far apart. The particles in a gas have few attractions between them. The particles in all states of matter are always moving.
Chemistry
2 answers:
djyliett [7]3 years ago
7 0
2)The particles in a liquid are moving past one another constantly.
3)The particles in gas move freely in all directions.
4)The particles in a solid vibrate in a fixed position.
6)The particles in a gas have few attractions between them.
7)The particles in all states of matter are always moving.
jasenka [17]3 years ago
5 0

Answer: The correct answers are "The particles in gas move freely in all directions" and "The particles in a gas have few attractions between them".

Explanation:

Kinetic-molecular theory postulates are as follows;

--The molecules of the gas are small and far apart.

--They are in constant in the random motion.

--The molecules of the gases collide with each other. They also collide with the walls of the container.

-- There is perfectly elastic collision between the gas molecules as there is no loss of kinetic energy.

--They do not exert repulsive or attractive forces on one another except during collision.

Therefore, the following are the statements related to kinetic-molecular theory from the given option;

The particles in gas move freely in all directions.

The particles in a gas have few attractions between them.

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2Mg + O2 → 2MgO<br><br> If you are burning 5.8332 g of Mg, how many grams of MgO will this make?
LekaFEV [45]
<h3>Answer:</h3>

9.6724 g MgO

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Chemistry</u>

<u>Stoichiometry</u>

  • Reading a Periodic Table
  • Using Dimensional Analysis
<h3>Explanation:</h3>

<u>Step 1: Define</u>

[RxN - Balanced] 2Mg + O₂ → 2MgO

[Given] 5.8332 g Mg

<u>Step 2: Identify Conversions</u>

[RxN] 2 mol Mg = 2 mol MgO

Molar Mass of Mg - 24.31 g/mol

Molar Mass of O - 16.00 g/mol

Molar Mass of MgO - 24.31 + 16.00 = 40.31 g/mol

<u>Step 3: Stoichiometry</u>

  1. Set up:                              \displaystyle 5.8332 \ g \ Mg(\frac{1 \ mol \ Mg}{24.31 \ g \ Mg})(\frac{2 \ mol \ MgO}{2 \ mol \ Mg})(\frac{40.31 \ g \ MgO}{1 \ mol \ MgO})
  2. Multiply/Divide:                                                                                               \displaystyle 9.67241 \ g \ MgO

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 5 sig figs.</em>

9.67241 g MgO ≈ 9.6724 g MgO

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