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Firlakuza [10]
3 years ago
5

What is a possible benefit of having the Food and Drug Administration (FDA) test a new drug instead of having the drug manufactu

rer test it?
Chemistry
2 answers:
Alex3 years ago
8 0
The FDA would have better authority i guess than the manufacturer and it would be safer for the FDA to test it out. Hope it helps
irinina [24]3 years ago
6 0

Answer: There are many possible benefits of having FDA for testing a new drug as compared to that of the manufacturer.

Explanation:

The FDA does not gain any financial support from the drugs but the manufacturers will gain financial benefit so there are chances that the manufacturer can cheat.

FDA can test the drugs on human beings and make sure that the drug is safe for both animals and human beings.

Manufacturer might be biased with his drug but FDA will give its decision based on the tests and the result will be unbiased.

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Be sure to answer all parts. Dinitrogen difluoride, N2F2, is the only stable, simple inorganic molecule with an N=N bond. The co
ASHA 777 [7]

(a) The molecular shapes of cis and Trans forms of N2F2 are-


b) There is EN difference between N atom and F atom. Hence the molecule will have a bond dipole.

In Cis form two fluorine atoms are on the same side of N N bond. Hence, bond moment in N2F2 cis form) do not cancel each other. Thus the cis form is polar.

In the trans form two fluorine atoms are on the opposite side of N-N bond. Bond moment of NF cancels each other.

Thus: trans N2F2 is non polar molecule.

3 0
4 years ago
Read 2 more answers
Calculate the wavelength of light emitted when each of the following transitions occur in the hydrogen atom. What type of electr
Len [333]

Answer:

a. 1875 nm

b. 4051 nm

c. 1282 nm

These all are infrared electromagnetic radiation.

Explanation:

Our strategy here is to utilize the Rydberg equation for hydrogen atom electronic transition.

1/λ = Rh x (1/n₁² - 1/n₂²)   where  λ is the wavelength

                                                   Rh is Rydberg constant

                                                   n₁ and n ₂ are the energy levels ( n₁ < n₂ )

Now lets star the calculations.

a.  n₁  = 3, n₂ = 4

1/λ = 1.097 x 10⁷ /m x (1/3² - 1/4²) = 5.333 x 10⁵/m

λ  = 1/(5.333 x 10⁵ /m) = 1.875 x 10⁻⁶ m

Converting λ to nanometers:

1.875 x 10⁻⁶ m x (1 x10⁹ nm/m) = 1875 nm

b.  n₁  = 4, n₂ = 5

1/λ = 1.097 x 10⁷ /m x  (1/4² - 1/5²) = 2.468 x 10⁵/m

λ  = 1/(2.468 x 10⁵/m) = 4.051 x 10⁻⁶ m

4.051 x 10⁻⁶ m x  (1 x10⁹ nm/m)  = 4051 nm

c.  n₁  = 3, n₂ = 5

1/λ = 1.097 x 10⁷ /m x  (1/3² - 1/5²) = 7801 x 10⁵/m

λ  = 1/(7801 x 10⁵/m) = 1282 x 10⁻⁶ m

1282 x 10⁻⁶ m x  (1 x10⁹ nm/m)  = 1282 nm

All of these transitions fall in the infrared region of the spectrum.

8 0
3 years ago
How would a solution that is labeled 5.0 M would be read as?
cestrela7 [59]
The M stands for molar, so it would be 5.0 molar. is that what you need?
7 0
3 years ago
The sodium atom contains 11 electrons, 11 protons, and 12 neutrons. what is the atomic mass of sodium?
Gnoma [55]
Atomic mass is the number of protons + number of neutrons. 11 protons + 12 neturons = 23
7 0
3 years ago
Which best describes oogenesis?​
kkurt [141]

Explanation:

Oogenesis can be defined as a process of differentiation of egg cell (ovum), into a mature ovum that further develops after fertilization. In humans, oogenesis begins in the early stage of embryonic development, during whcih primary oocyte performs meiosis I and forms secondary oocyte.

6 0
3 years ago
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