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Firlakuza [10]
3 years ago
5

What is a possible benefit of having the Food and Drug Administration (FDA) test a new drug instead of having the drug manufactu

rer test it?
Chemistry
2 answers:
Alex3 years ago
8 0
The FDA would have better authority i guess than the manufacturer and it would be safer for the FDA to test it out. Hope it helps
irinina [24]3 years ago
6 0

Answer: There are many possible benefits of having FDA for testing a new drug as compared to that of the manufacturer.

Explanation:

The FDA does not gain any financial support from the drugs but the manufacturers will gain financial benefit so there are chances that the manufacturer can cheat.

FDA can test the drugs on human beings and make sure that the drug is safe for both animals and human beings.

Manufacturer might be biased with his drug but FDA will give its decision based on the tests and the result will be unbiased.

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How many covalent bonds does carbon form in neutral compounds?
soldi70 [24.7K]
The answer to this question is 5
4 0
3 years ago
Ben put 100 ml of water and 100 ml of oil in a beaker then he stirred the mixture. Which is the best way to quickly separate the
RSB [31]

To separate oil from water, add a solution of soluble ionic salt to the solution. Distillation, which involves boiling and condensing the water, is another option, as well as partially freezing the oil and water combination and discarding one-fourth to one-third of the unfrozen water.


4 0
3 years ago
Why do atoms go through radioactive decay?
Alecsey [184]
They go through radioactive decay because when atoms are unstable by going through it they are emitting radiation in natural process and they gain stability by losing energy.
8 0
3 years ago
For the following electrochemical reaction: Al3+(aq) + 3e -> Al(s) Eº = -1.66 V E° = 2.87 F2(g) + 2e -> 2F (aq) Calculate
makvit [3.9K]

<u>Answer:</u> The standard electrode potential of the cell is 4.53 V.

<u>Explanation:</u>

We are given:

E^o_{(F_2/F^-)}=2.87V\\E^o_{(Al^{3+}/Al)}=-1.66V

The substance having highest positive E^o potential will always get reduced and will undergo reduction reaction. Here, fluorine will undergo reduction reaction will get reduced.

Aluminium will undergo oxidation reaction and will get oxidized.

Substance getting oxidized always act as anode and the one getting reduced always act as cathode.

To calculate the E^o_{cell} of the reaction, we use the equation:

E^o_{cell}=E^o_{cathode}-E^o_{anode}

E^o_{cell}=2.87-(-1.66)=4.53V

Hence, the standard electrode potential of the cell is 4.53 V.

6 0
3 years ago
If the conjugate base of a molecule has a pkb of 1.4, what would you expect the molecule to be?
maw [93]

If the conjugate base of a molecule has a pKb of 1.4, the molecule should be a Weak Acid.

Notice this question gives us the pKb of the molecule, not the pKa. Because of this, the pH scale basically gets reversed, so lower numbers in pKb correlate with stronger bases, and higher numbers in pKb correlate with stronger acids - the exact opposite of the pH scale.

It's important to make sure you completely understand the terms of conjugate base, conjugate acid, pKb, pKa, and how they all relate. It's easy to mix up the meanings of these definitions.

Here are the two other pieces of information you need to know to correctly answer this question:

  • Strong acids have a weak conjugate base.
  • Strong bases have a weak conjugate acid.

So if the problem says you have a strong conjugate base, then the molecule must be a weak acid. To illustrate this, think of ammonium, NH4+. Ammonium is a weak acid, but the conjugate base of ammonium is ammonia, NH3, which is a reasonably good base.

Learn more about conjugate base here : brainly.com/question/22514615

#SPJ4

3 0
2 years ago
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