V=84.0 mL = 84.0 cm³
m=609.0 g
p=m/v
p=609.0/84.0=7.25 g/cm³
Explanation:
Structural Formulas v. Empirical Formulas
An empirical formula (like a molecular formula) lacks any structural information about the positioning or bonding of atoms in a molecule. It can therefore describe a number of different structures, or isomers, with varying physical properties. For butane and isobutane, the empirical formula for both molecules is C2H5, and they share the same molecular formula, C4H10. However, one structural representation for butane is CH3CH2CH2CH3, while isobutane can be described using the structural formula (CH3)3CH.
Answer:
276g of Br are present
Explanation:
To solve this question we need to find the moles of CaBr2 using its molar mass -CaBr2: 199.89g/mol-. As 1 mole of CaBr2 contains 2 moles of Br we can find the moles of Br and its mass:
<em>Moles CaBr2:</em>
345g * (1mol/199.89g) = 1.7259 moles CaBr2
<em>Moles Br:</em>
1.7259 moles CaBr2 * (2mol Br / 1mol CaBr2) = 3.4519 moles Br
<em>Mass Br -Molar mass: 79.904g/mol-</em>
3.4519 moles Br * (79.904g/mol) = 276g of Br are present
The answer would be B: Walking instead of driving a car to get to the library.
Explanation: Walking instead of driving conserves gas and puts less fumes into the environment.