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stira [4]
2 years ago
5

When considering metal complexation with EDTA, if you are comparing 2 metals, the metal with a higher ____________ will react wi

th EDTA first.
Chemistry
1 answer:
DENIUS [597]2 years ago
7 0

If you are comparing 2 metals, the metal with a higher <u>Number of free ions</u> will react with EDTA first

<h3>What is EDTA ?</h3>

EDTA is a type of chemical which binds certain metal ions such as calcium and magnesium. some of the functions of EDTA  includes:

  • Preventing blood clotting of blood samples
  • prevention of the formation of Biofilm by bacterias

The EDTA will readily react with metals which have a hiogher number of free ions that it can bind with.

Hence we can conclude that If you are comparing 2 metals, the metal with a higher <u>Number of free ions</u> will react with EDTA first.

Learn more about EDTA : brainly.com/question/10818175

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PLZ HELP IM FAILING SCIENCE
Leni [432]

Answer:

Cleaning up oil spills and metal contaminates in a low-impact, sustainable and inexpensive manner remains a challenge for companies and governments globally.

But a group of researchers at UW–Madison is examining alternative materials that can be modified to absorb oil and chemicals. If further developed, the technology may offer a cheaper and “greener” method to absorb oil and heavy metals from water and other surfaces.

Aerogels, which are highly porous materials and the lightest solids in existence, are already used in a variety of applications, ranging from insulation and aerospace materials to thickening agents in paints. The aerogel prepared in Gong’s lab is made of cellulose nanofibrils (sustainable wood-based materials) and an environmentally friendly polymer. Furthermore, these cellulose-based aerogels are made using an environmentally friendly freeze-drying process without the use of organic solvents.

It’s the combination of this “greener"material and its high performance that got Gong’s attention.

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6 0
3 years ago
Whats principle of Aristotle's do scientist use today
Darina [25.2K]
His observation and census.
6 0
3 years ago
A container holds 0.490 m3 of oxygen at an absolute pressure of 5.00 atm. A valve is opened, allowing the gas to drive a piston,
mash [69]

<u>Answer:</u> The new volume will be 2.04m^3

<u>Explanation:</u>

To calculate the new volume, we use the equation given by Boyle's law. This law states that pressure is directly proportional to the volume of the gas at constant temperature.

The equation given by this law is:

P_1V_1=P_2V_2            (at constant temperature)

where,

P_1\text{ and }V_1 are initial pressure and volume.

P_2\text{ and }V_2 are final pressure and volume.

We are given:

P_1=5.00atm\\V_1=0.490m^3\\P_2=1.20atm\\V_2=?m^3

Putting values in above equation, we get:

5atm\times 0.490m^3=1.20\times V_2\\\\V_2=2.04m^3

Hence, the new volume will be 2.04m^3

5 0
3 years ago
Calculate the volume in liters of a M barium chloride solution that contains of barium chloride . Round your answer to significa
Reptile [31]

Answer:

1.667L of a 0.30M BaCl₂ solution

Explanation:

<em>Of a 0.30M barium chloride, contains 500.0mmol of barium chloride.</em>

<em />

Molarity is an unit of concentration used in chemistry defined as the moles of solute present in 1 liter of solution.

In a 0.30M BaCl₂ solution there are 0.30 moles of BaCl₂ in 1 liter of solution.

Now, in your solution you have 500mmol of BaCl₂ = 0.500 moles of BaCl₂ (1000 mmol = 1 mol). Thus, 0.500 moles of BaCl₂ are present in:

0.500 moles * (1L / 0.30 moles) =

<h3>1.667L of a 0.30M BaCl₂ solution</h3>
5 0
3 years ago
How many milliliters of a 0.40%(w/v) solution of nalorphine must be injected to obtain a dose of 1.5 mg?
ozzi
The number  of Ml  of  a  0.40 %w/v solution  of   ,nalorphine  that must  be injected  to  obtain  a  dose  of 1.5 mg is  calculated as  below


since M/v%   is  mass  of solute  in  grams per 100  ml

convert Mg to  g
1 g = 1000 mg  what  about  1.5 mg =?  grams
=   1.5 /1000 = 0.0015 grams


volume is therefore =  100 (  mass/ M/v%)

= 100  x(  0.0015/ 0.4) =  0.375  ML
6 0
4 years ago
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