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d1i1m1o1n [39]
3 years ago
9

Please help a girl out

Chemistry
2 answers:
NISA [10]3 years ago
7 0
I think it’ll be option B.
frosja888 [35]3 years ago
4 0
B I think it is just logic I guess
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How many moles of chlorine are used up in a reaction that produces 0.35kg of BCl3
maw [93]

4.48 mol Cl2. A reaction that produces 0.35 kg of BCl3 will use 4.48 mol of Cl2.

(a) The <em>balanced chemical equation </em>is

2B + 3Cl2 → 2BCl3

(b) Convert kilograms of BCl3 to moles of BCl3

MM: B = 10.81; Cl = 35.45; BCl3 = 117.16

Moles of BCl3 = 350 g BCl3 x (1 mol BCl3/117.16 g BCl3) = 2.987 mol BCl3

(c) Use the <em>molar ratio</em> of Cl2:BCl3 to calculate the moles of Cl2.

Moles of Cl2 = 2.987 mol BCl3 x (3 mol Cl2/2 mol BCl3) = 4.48 mol Cl2

4 0
3 years ago
Hey guys please help me
Anvisha [2.4K]

Answer:

Water will move out of the eggplant cells and the cells will shrink.

Explanation:

I found it on a Quizziz.

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2 years ago
Explain why the male angler fish is small and does not require a fully formed gut
Arturiano [62]

Answer:They are small because they don't need larger bodies to enable them attach to the females. They don't have fully formed gut because when they reach adulthood their digestive system stops functioning.

Explanation:they then find a female angler fish, attach by bitting into her flesh and fusing to her body. So whatever she eats they eat too.

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3 years ago
If you observe a Full Moon on January 12th, on what date would you observe the next New Moon?
AlexFokin [52]

January 19

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8 0
3 years ago
How much heat is required to warm 1.50L of water from 25.0C to 100.0C? (Assume a density of 1.0g/mL for the water.)
Masteriza [31]

<u>Answer:</u> The amount of heat required to warm given amount of water is 470.9 kJ

<u>Explanation:</u>

To calculate the mass of water, we use the equation:

\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}

Density of water = 1 g/mL

Volume of water = 1.50 L = 1500 mL    (Conversion factor:  1 L = 1000 mL)

Putting values in above equation, we get:

1g/mL=\frac{\text{Mass of water}}{1500mL}\\\\\text{Mass of water}=(1g/mL\times 1500mL)=1500g

To calculate the heat absorbed by the water, we use the equation:

q=mc\Delta T

where,

q = heat absorbed

m = mass of water = 1500 g

c = heat capacity of water = 4.186 J/g°C

\Delta T = change in temperature = T_2-T_1=(100-25)^oC=75^oC

Putting values in above equation, we get:

q=1500g\times 4.186J/g^oC\times 75^oC=470925J=470.9kJ

Hence, the amount of heat required to warm given amount of water is 470.9 kJ

6 0
3 years ago
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