Answer:
These defensive driving skills can help you avoid the dangers caused by other ... being aware of the cars around you, checking your mirrors — the list goes on. ... It's not just teen drivers who are at fault: People who have been driving for a while ... car and a slow-moving truck in the same lane, it's a pretty sure bet the driver ...
Explanation:
Charles’ law: V1/T1 = V2/T2. The volume and temperature of a fixed amount of gas at a constant pressure are directly proportional. To use the equation, the temperature must be in Kelvin.
V2 = V1T2/T1 = (43 L)(280.15 K)/(373.15 K)
V2 = 32 L
The correct answer choice would thus be B.

Now, question is why MgO but not CaO.
At a dissociation pressure of 1 atm, the temperature at which CO2 and metal oxide is formed is :
For MgCO3 = 540 °C
For CaCO3 = 900 °C”
Also,
<span>The driving force is the larger lattice energy of MgO(3795) vs that of CaO(3414 kJ mol^-1) . More the lattice energy, the more chances of that compound to form.</span>
So MgO is formed first.
Carbonate is Calcium carbonate
<u>Answer:</u> The mass of the nitrous oxide gas produced is 0.011 kg.
<u>Explanation:</u>
To calculate the mass of the gas, we use the formula:

We are given:
Specific density of the gas = 
Mass of the gas = ? kg
Volume of the gas =
(Conversion Factor:
)
Putting values in above equation, we get:


Hence, the mass of the nitrous oxide gas produced is 0.011 kg.
<u>Answer:</u> The final temperature of the mixture is 51.49°C
<u>Explanation:</u>
When two samples of water are mixed, the heat released by the water at high temperature will be equal to the amount of heat absorbed by water at low temperature

The equation used to calculate heat released or absorbed follows:

......(1)
where,
q = heat absorbed or released
= mass of water at high temperature = 140 g (Density of water = 1.00 g/mL)
= mass of water at low temperature = 230 g
= final temperature = ?°C
= initial temperature of water at high temperature = 95.00°C
= initial temperature of water at low temperature = 25.00°C
c = specific heat of water= 4.186 J/g°C
Putting values in equation 1, we get:
![140\times 4.186\times (T_{final}-95)=-[230\times 4.186\times (T_{final}-25)]](https://tex.z-dn.net/?f=140%5Ctimes%204.186%5Ctimes%20%28T_%7Bfinal%7D-95%29%3D-%5B230%5Ctimes%204.186%5Ctimes%20%28T_%7Bfinal%7D-25%29%5D)

Hence, the final temperature of the mixture is 51.49°C