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Romashka-Z-Leto [24]
3 years ago
5

How many grams of silver bromide are produced when 505 grams of cobalt (III) bromide reacts completely in the following equation

:
1 CoBr3 + 3 AgNO3 à 3 AgBr + 1 Co(NO3)3
Chemistry
1 answer:
DedPeter [7]3 years ago
7 0
Mass = 473.2 g
Explanation:
Given data:
Mass of cobalt(III) nitrate = 206 g
Mass of silver bromide produced = ?
Solution:
Chemical equation:
CoBr₃ + 3AgNO₃ → 3AgBr + Co(NO₃)₃
Number of moles of cobalt(III) nitrate:
Number of moles = mass/ molar mass
Number of moles = 206 g/ 245 g/mol
Number of moles = 0.84 mol
Now we will compare the moles of cobalt(III) nitrate with silver bromide.
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Determine the limiting reactant (lr) and the mass (in g) of nitrogen that can be formed from 50.0 g n2o4 and 45.0 g n2h4. some p
Licemer1 [7]
                                                   N2O4(l) + 2 N2H4(l) → 3 N2(g) + 4 H2O(g)
1) to calculate the limiting reactant you need to pass grams to moles.
<span> moles is calculated by dividing mass by molar mass
</span>
mass of N2O4: 50.0 g 
molar mass of <span>N2O4 = 92.02 g/mol
</span><span>molar mass of N2H4 = 32.05 g/mol.
</span>mass of N2H4:45.0 g

moles N2O4=50.0/92.02 g/mol= 0,54 mol of N2O4
moles N2H4= 45/32.05 g/mol= 1,40 mol of <span><span>N2H4

</span> 2)</span>
By looking at the balanced equation, you can see that 1 mol of N2O4 needs 2 moles of N2H4 to fully react . So to react  0,54 moles of N2O4, you need 2x0,54 moles of <span>N2H4 moles
</span><span>N2H4 needed = 1,08 moles.
You have more that 1,08 moles </span><span>N2H4, so this means the limiting reagent is not N2H4, it's </span>N2O4. The molecule that has molecules that are left is never the limiting reactant.

3) 1 mol of N2O4 reacting, will produce 3 mol of N2 (look at the equation)
There are 0,54 mol of N2O4 available to react, so how many moles will produce of N2?
1 mol N2O4------------3 mol of N2
0,54 mol N2O4--------x
x=1,62 mol of N2

4) the only thing left to do is convert the moles obtained, to grams.
We use the same formula as before, moles equal to mass divided by molar mass.
moles= \frac{grams}{molar mass}             (molar mass of N2= 28)
1,62 mol of N2= mass/ 28
mass of N2= 45,36 grams

4 0
3 years ago
Identify each statement as true or false. Explain in every case.a.Ionization energies are always negative quantities.b.Oxygen ha
worty [1.4K]

Answer:

(a) FALSE

(b) FALSE

(c) TRUE

(d) FALSE

Explanation:

Ionization energy refers to the energy needed for removal of a valence electron present in valence shell of a gaseous atom.

(a) <u>The value of ionization energy of an atom is always</u><u> positive</u>. This is because energy has to be always supplied or provided to a gaseous atom for the removal of the valence electron.

<em><u>Therefore, the statement (A) is</u></em><em><u> false</u></em>

   

(b) The ionization energy of an atom <u>increases across a period</u> i.e. from left to right. This is because the <u>effective nuclear charge that is experienced by the valence electron increases</u> from left to right in the periodic table, as the atomic number increases.

So, more energy is required to remove the valence electron of fluorine as compared to oxygen.

<u>Therefore, the </u><u>ionization energy of fluorine is greater than oxygen</u><u>.</u>

<em><u>Therefore, the statement (B) is</u></em><em><u> false</u></em>

(c) <u>First ionization energy</u> is energy needed for removal of first electron present in valence shell of a neutral atom. Whereas, <u>second ionization energy</u> is the energy needed for removal of second electron present in valence shell of a monovalent cation

The second ionization energy of an atom is always greater than the first ionization energy. This is because removing<u> an electron from a positively charged species, requires more energy.</u>

<em><u>Therefore, the statement (C) is</u></em><em><u> true</u></em>

<em><u /></em>

(d) <u>The third ionization energy </u>refers to the energy needed to remove the third electron from a divalent cation.

<em><u>Therefore, the statement (D) is</u></em><em><u> false</u></em>

7 0
3 years ago
In an experiment to find the concentration of calcium hydroxide in limewater , 25.0 cm3 of limewater needed 18.8 cm3 of 0.0400 m
Andre45 [30]

Answer:

0.01504 mol/dm3

Explanation:

Calcium Hydroxide - Ca(OH)2

Hydrochloric acid - HCl

The reaction between both is given as;

2HCl   +   Ca(OH)2   --> CaCl2  + 2H2O

2   :  1

The relationship between the concentration and volume is given as;

CaVa  /  CbVb = na  /  nb

where a = acid (HCl) and b = base Ca(OH)2

Inserting the values;

0.04 * 18.8  /  (Cb * 25)  =  2 / 1

0.752 / 25Cb = 2

Cb = 0.752 / 50  = 0.01504

6 0
3 years ago
What is the anion found in phosphoric acid?
Hoochie [10]
...contains the sulfate anion (SO42−) and is called sulfuric acid; H3PO4<span> contains the phosphate anion (PO43−) and is called phosphoric acid; and HC2H3O2, which contains the acetate ion (C2H3O2−), is c... Phosphoric acid (</span>H3PO4<span>) has three hydrogen atoms, all of which are replaceable by a metal.</span>
7 0
3 years ago
Read 2 more answers
When harmful bacteria invade a wound, the skin around the wound turns red. This is known as:
nasty-shy [4]

Answer:

Inflammation

Explanation:

Inflammation is the response to a cut. The blood vessels expand when you get cut to allow white blood cells to flock to the wound site. These attack any bacteria that got past the clot. If you mean <u>excess</u> bacteria, then that would be an infection.

4 0
3 years ago
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