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3 years ago

What is the number if moles of nitrogen gas which react with 18 g of magnesium to form magnesium nitride compound?(mg=24,N=14)

Chemistry

1 answer:

makvit [3.9K]3 years ago

6 0

Answer:

It is true. a) 0.25 mol

Explanation:

Hello there?

To begin solving this problem, you have to write down the chemical equation and make sure it is well balanced.

The chemical equation is;

3Mg(s) + N2(g) => Mg3N2(s)

1 mole of Mg = 24g

We have 18g of Magnesium (Mg) reacting with Nitrogen gas (N2)

From our equation,

Mole ratio = 3 : 1, (Mg : N2)

1 mol Mg = 24g

x mol Mg = 18g

x mol Mg = (18/24) = 0.75 mol Mg

But mole ratio = 3 : 1 (Mg : N2)

This means that 3 => 0.75 mol Mg

What about ratio 1 of N2?

N2 = (0.75 mol ÷ 3)/1

= 0.25 mol N2

I hope this helps you to understand better. Have a nice studies. 

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