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pshichka [43]
2 years ago
7

What is the number if moles of nitrogen gas which react with 18 g of magnesium to form magnesium nitride compound?(mg=24,N=14)

Chemistry
1 answer:
makvit [3.9K]2 years ago
6 0

Answer:

It is true. a) 0.25 mol

Explanation:

<em>Hello </em><em>there?</em>

To begin solving this problem, you have to write down the chemical equation and make sure it is well balanced.

The chemical equation is;

3Mg(s) + N2(g) => Mg3N2(s)

1 mole of Mg = 24g

We have 18g of Magnesium (Mg) reacting with Nitrogen gas (N2)

From our equation,

Mole ratio = 3 : 1, (Mg : N2)

1 mol Mg = 24g

x mol Mg = 18g

x mol Mg = (18/24) = 0.75 mol Mg

But mole ratio = 3 : 1 (Mg : N2)

This means that 3 => 0.75 mol Mg

What about ratio 1 of N2?

N2 = (0.75 mol ÷ 3)/1

= 0.25 mol N2

<em>I </em><em>hope</em><em> </em><em>this </em><em>helps</em><em> </em><em>you </em><em>to </em><em>understand</em><em> </em><em>better</em><em>.</em><em> </em><em>Ha</em><em>v</em><em>e </em><em>a </em><em>nice </em><em>studies.</em><em> </em><em />

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Answer:

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Slav-nsk [51]
Answer is: pH value of solution of NaC₂H₃O₂ is 9.07.
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Ka(HC₂H₃O₂) = 1,8·10⁻⁵.<span>
Ka · Kb = Kw.
</span>1,8·10⁻⁵ mol/dm³ · Kb = 1·10⁻¹⁴ mol²/dm⁶; the ionic product of water at 25°C.<span>
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Answer:   19.71 feet

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