Answer:
C
Explanation:
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Answer:
A. True
B. True
C. False
D. False
Explanation:
Electrons travel around the nucleus in circular orbits and moves from one orbit to another orbit when they absorb energy or lose energy. The Bohr atom is the model currently accepted for electrons in atoms because this model provides the right information about presence of electrons around the orbits. Scientists know the energies of electrons as well as the areas (orbitals) where the electrons are probably located with the help of new technology.
1. NA = Sodium, NA was the chemicals symbols for the element would be NA because in Latin it is natrium for natron in which is sodium in English, Sodium was created by Humphry Davy in the year of 1807. Element name Sodium, Chemical symbol NA atomic number, 11 Atomic mass 23.
2. AG = Sliver, AG was the chemicals symbols for the element would be AG because in Latin it is argentum in which in English means bright and also sliver. Element name Sliver Chemical symbol AG atomic number, 47 Atomic mass 108.
Answer:
See explanation below
Explanation:
To get this, we need to apply the general expression for half life decay:
N = N₀e(-λt) (1)
Where:
N and N₀ would be the final and innitial quantities, in this case, masses.
t: time required to decay
λ: factor related to half life
From the above expression we need λ and t. To get λ we use the following expression:
λ = t₁₂/ln2 (2)
And we have the value of half life, so, replacing we have:
λ = 8.04 / ln2 = 11.6
Now, we can replace in (1) and then, solve for t:
0.75 = 40 exp(-11.6t)
0.75 / 40 = exp(-11.6t)
ln(0.01875) = -11.6t
-3.9766 = -11.6t
t = -3.9766 / -11.6
<h2>
t = 0.34 days</h2><h2>
</h2>
Explanation:
The given data is as follows.
Concentration of standard NaOH solution = 0.1922 M
Let the original acid solution concentration be x.
= 0.1 x M
= 10.00 mL (given)
The reaction equation is as follows.
Concentration × Volume of 
= Concentration × Volume of NaOH
x = 1.314 M
Therefore, we can conclude that the concentration of the original sulfuric acid solution is 1.314 M.
