Answer:
N(CO2) = n(CO2) x Avogadros constant
n(CO2) = mass(CO2)/Molar mass(CO2) = 112/44 = 2.5454….
N(CO2) = 2.545454… x (6.02 x 10^23) = 1.5323636 x 10^24
Therefore, the number of CO2 molecules in 112 g of CO2 = 1.53 x 10^24 molecules
Transitional elements are usually described as elements of the d block. oxygen is not in the d block, and hence is not a transitional element.
Answer:
Explanation:
The <u>mass of polymer in the order recieved</u> is:
- 3000 lb * 13/100 = 390 lb
The <u>mass of polymer in the 10% solution</u> is:
So to solve this problem, <em>we need to add (390-50) 340 lb of polymer that comes from the 20% solution</em>.
We<u> calculate the mass of the 20% solution that would contain 340 lb of polymer</u>:
- 340 lb * 100/20 = 1700 lb
So far, in total <em>we have a solution that weighs (1700+500) 2200 lb and contains 390 lb of polymer</em>.
Thus, in order to reach the required mass of solution (and percentage of polymer by weight), <u>we add</u> (3000-2200) <u>800 lb of pure solvent</u>.