Answer:
Approx. 4⋅g.
Explanation:
Moles of sulfuric acid =10.0⋅g98.08⋅g⋅mol−1=0.102⋅mol.
Now we have the molar quantity of sulfuric acid that react; we also have the stoichiometric equation that shows the molar equivalence of sulfuric acid, and lithium hydroxide.
Given the stoichiometry,
mass of water =0.102⋅mol×2×18.01.g.mol−1=??⋅g.
Why did I multiply the mass in this equation by 2? Am I pulling your leg?
Answer:
b. Its concentration is half that of the chloride ion
Explanation:
As the calcium chloride formula is CaCl2
CaCl2 <--> Ca + 2 Cl-
Explanation:
Given problem:
Find the molar mass of:
SO₃ and C₁₀H₈
Solution:
The molar mass of a compound is the mass in grams of one mole of the substance.
To solve this, we are going to add the individual atomic masses of the elements in the compound;
Atomic mass;
S = 32g/mol; O = 16g/mol; C = 12g/mol and H = 1g/mol
For SO₃;
= 32 + 3(16)
= 32 + 48
= 80g/mol
For C₁₀H₈
= 10(12) + 8(1)
= 120 + 8
= 128g/mol
We can solve this problem by using Henry's law.
Henry's law states that the amount of dissolved gas is proportional to its partial pressure.

C is <span>the solubility of a gas.
</span><span>k is Henry's law constant.
</span><span>P is the partial pressure of the gas.
</span>We can calculate the constant from the first piece of information and then use Henry's law to calculate solubility in open drink.
0.12=4k
k=0.03
Now we can calculate the solubility in open drink.


Now we need to convert it to g/L. One mol of CO2 is 44.01<span>g.
</span>The final answer is:
Answer:
1) 0.423 m
2) 3.107 mi
3) 68.18 kg
4) 0.0083 mem
5) 0.528 gal
6) 4300 mL
7) 32.4 mem
8) 523.013 km
9) 70.866 in
10) 2.3 yek
Note: I can’t type the about equal to sign or the sign that shows a repeating decimal, so check the image for that and my work.
Explanation: