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3 years ago

Describe and name the parts of the atom.

Chemistry

2 answers:

Elan Coil [88]3 years ago

8 0

Answer:

protons, electrons, and neutrons.

A proton is positively charged and is located in the center or nucleus of the atom.

Electrons are negatively charged and are located in rings or orbits spinning around the nucleus.

The number of protons and electrons is always equal.

Explanation:

Setler79 [48]3 years ago

4 0

Answer:

The parts of an atom are protons, electrons, and neutrons.

A proton is positively charged and is located in the center or nucleus of the atom.

Electrons are negatively charged and are located in rings or orbits spinning around the nucleus.

The number of protons and electrons is always equal.

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Is o-toluic acid soluble in ether, NaOH?, Is Napthalene soluble in NaOH?

natima [27]

Yes, o-toluic acid is soluble in ether as ether is slightly polar and it is soluble in NaOH because it is likely to form soluble compounds with it.

Naphthalene is insoluble in NaOH.

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3 years ago

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Paladinen [302]

A) the DNA copies itself

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3 years ago

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Find the density of a material given that a 5.03g sample occupies 3.24ml

Verizon [17]

Formula for density:

D = Mass / Volume

Mass = 5.03g

Volume = 3.24ml

Formula in our case:

D = 5.03 / 3.24

$D = 0.31~g/m^{3}$

Hope it helped,

BioTeacher101

3 0

3 years ago

Lead(II) nitrate, Pb(NO3)2, and potassium iodide, KI net ionic equation:

MissTica

Answer:

Pb²⁺ (aq) + 2I⁻ (aq) → PbI₂ (s)

General Formulas and Concepts:

Solubility Rules
Reaction Prediction

Explanation:

Step 1: RxN

Pb(NO₃)₂ (aq) + KI (aq) → PbI₂ (s) + KNO₃ (aq)

Step 2: Balance RxN

Pb(NO₃)₂ (aq) + 2KI (aq) → PbI₂ (s) + 2KNO₃ (aq)

Step 3: Ionic Equations

Total Ionic Equation:

Pb²⁺ (aq) + 2NO₃⁻ (aq) + 2K⁺ (aq) + 2I⁻ (aq) → PbI₂ (s) + 2K⁺ (aq) + 2NO₃⁻ (aq)

Cancel out spectator ions.

Net Ionic Equation:

Pb²⁺ (aq) + 2I⁻ (aq) → PbI₂ (s)

7 0

3 years ago

Assuming an efficiency of 30.80%, calculate the actual yield of magnesium nitrate formed from 147.4g of magnesium and excess cop

Reil [10]

Answer:

The answer to your question is 280 g of Mg(NO₃)₂

Explanation:

Data

Efficiency = 30.80 %

Mg(NO₃)₂ = ?

Magnesium = 147.4 g

Copper (II) nitrate = excess

Balanced Reaction

Mg + Cu(NO₃)₂ ⇒ Mg(NO₃)₂ + Cu

Reactants Elements Products

1 Mg 1

1 Cu 1

2 N 2

6 O 6

Process

1.- Calculate the theoretical yield

Molecular weight Mg = 24

Molecular weight Mg(NO₃)₂ = 24 + (14 x 2) + (16 x 6)

= 24 + 28 + 96

= 148 g

24 g of Mg -------------------- 148 g of Mg(NO₃)₂

147.4 g of Mg ------------------- x

x = (147.4 x 148) / 24

x = 908.96 g of Mg(NO₃)₂

2.- Calculate the Actual yield

yield percent = $\frac{actual yield}{theoretical yield}$

Solve for actual yield

Actual yield = Yield percent x Theoretical yield

Substitution

Actual yield = $\frac{30.8}{100}$ x 908.96

Actual yield = 279.95 ≈ 280g

4 0

3 years ago

￼ Describe and name the parts of the atom.

Describe and name the parts of the atom.