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inna [77]
3 years ago
15

What determines the path that an object in projectile motion follows

Physics
2 answers:
Juli2301 [7.4K]3 years ago
6 0

ANSWER:

C) Gravity & Inertia.

<u>Choices </u>

A) gravity only

B) inertia and air resistance

C) gravity and inertia

D) gravity and air resistance

Ilia_Sergeevich [38]3 years ago
3 0
 <span>Direction and magnitude it is also </span>determined<span> by the gravitational acceleration any impacts or interruptions are ignored. </span>
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A car is traveling south is 200 kilometers from it’s starting point after 2 hours. What is the average velocity of the car
Lesechka [4]

Answer:

100

Explanation:

take note that v=d/t (velocity is distance over(divided by) time, so in this case it would be 200 (distance) divided by 2 (time) = 100

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Mga peymos d nang papallow back yan un follow ko na kayu mga bubu​
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<h2> Ah Filipino ka rin?</h2>

Explanation:

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Another circuit question. So far I've incorrectly done this one 3 out of 5 times lol
marta [7]
Hope this helps you.

7 0
4 years ago
PLEASE HELP
Paul [167]
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7 0
1 year ago
if the vessel in the sample problem accelerates fir 1.00 min, what will its speed be after that minute ?
LUCKY_DIMON [66]

Answers:

a) 154.08 m/s=554.68 km/h

b) 108 m/s=388.8 km/h

Explanation:

<u>The complete question is written below: </u>

<u></u>

<em>In 1977 off the coast of Australia, the fastest speed by a vessel on the water was achieved. If this vessel were to undergo an average acceleration of 1.80 m/s^{2}, it would go from rest to its top speed in 85.6 s.  </em>

<em>a) What was the speed of the vessel? </em>

<em> </em>

<em>b) If the vessel in the sample problem accelerates for 1.00 min, what will its speed be after that minute? </em>

<em></em>

<em>Calculate the answers in both meters per second and kilometers per hour</em>

<em></em>

a) The average acceleration a_{av} is expressed as:

a_{av}=\frac{\Delta V}{\Delta t}=\frac{V-V_{o}}{\Delta t} (1)

Where:

a_{av}=1.80 m/s^{2}

\Delta V is the variation of velocity in a given time \Delta t, which is the difference between the final velocity V and the initial velocity V_{o}=0 (because it starts from rest).

\Delta t=85.6 s

Isolating V from (1):

V=a_{av}\Delta t + V_{o} (2)

V=(1.80 m/s^{2})(85.6 s) + 0 m/s (3)

V=154.08 \frac{m}{s} (4)

If 1 km=1000m and 1 h=3600 s then:

V=154.08 \frac{m}{s}=554.68 \frac{km}{h} (4)

b) Now we need to find the final velocity when \Delta t=1 min=60 s:

<em></em>

V=(1.80 m/s^{2})(60 s) + 0 m/s (5)

V=108 \frac{m}{s}=388.8 \frac{km}{h} (6)

5 0
3 years ago
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