All categories

4 years ago

Your code returns a number of 99.123456789 +0.00455679 for your calculation. How should you report it in your lab write-up?

Physics

1 answer:

Aneli [31]4 years ago

6 0

Answer: Your code returns a number of 99.123456789 +0.00455679

Ok, you must see where the error starts to affect your number.

In this case, is in the third decimal.

So you will write 99.123 +- 0.004 da da da.

But you must round your results. In the number you can see that after the 3 comes a 4, so the 3 stays as it is.

in the error, after the 4 comes a 5, so it rounds up.

So the final presentation will be 99.123 +- 0.005

you are discarding all the other decimals because the error "domains" them.

You might be interested in

Fluid clutches are used on equipment that is subjected to?

mamaluj [8]

Fluid clutches are used on equipment that is subjected to higher torque per unit volume. This type of clutch makes use of an incompressible fluid like oil in order to transfer the input of a movement from a pedal and cylinder to an actuating cylinder. Releasing the this clutch would stop the transfer of power but still allowing the engine to turn continuously.

4 0

3 years ago

Determine the launch speed of a horizontally launched cannonball that lands 26.3

nlexa [21]

Answer:

The cannon has an initial speed of 13.25 m/s.

Explanation:

The launched cannonball is an example of a projectile. Thus, its launch speed can be determined by the application of the formula;

R = u $\sqrt{\frac{2H}{g} }$

Where: R is the range of the projectile, u is its initial speed, H is the height of the cliff and g is the gravitaty.

R = 26.3 m, H = 19.3 m, g = 9.8 m/ $s^{2}$ .

So that:

26.3 = u $\sqrt{\frac{2*19.3}{9.8} }$

$(26.3)^{2}$ = $u^{2}$ x $\frac{38.6}{9.8}$

691.69 = $u^{2}$ x $\frac{38.6}{9.8}$

$u^{2}$ = $\frac{691.69*9.8}{38.6}$

= $\frac{6778.562}{38.6}$

$u^{2}$ = 175.6104

⇒ u = $\sqrt{175.6104}$

= 13.2518

u = 13.25 m/s

The initial speed of the cannon is 13.25 m/s.

4 0

3 years ago

In getting ready to slam-dunk the ball, a basketball player starts from rest and sprints to a speed of 4.82 m/s in 1.98 s. Assu

Ann [662]

Great equation: distance = rate*time

So, distance run = 4.82 meters/second * 1.98 seconds = 9.5436 meters (round according to whatever the problem specifies, usually to the tenths or hundredths is sufficient).

This makes sense if you think about it since you are multiplying seconds with meters over seconds. The seconds cancel out, leaving you only the meters.

7 0

3 years ago

The fluid pressure 10 ft underwater is _____ the fluid pressure 5 ft underwater. A.less than or greater than, depending on what

just olya [345]

I would say greater than because as you do deeper, the pressure strengthens. If you were in a 10 ft deep pool and you dive all the way to the bottom, the ears usually pop. That's because of the pressure. Whereas if you were to go five feet, your ears wouldn't. It depends on the age of the person. Hope this helps.

5 0

4 years ago

Suppose that a charged particle of diameter 1.00 micrometer moves with constant speed in an electric field of magnitude 1.00×105

Dovator [93]

It's a bit of a trick question, had the same one on my homework. You're given an electric field strength (1*10^5 N/C for mine), a drag force (7.25*10^-11 N) and the critical info is that it's moving with constant velocity(the particle is in equilibrium/not accelerating).
All you need is F=(K*Q1*Q2)/r^2 
Just set F=the drag force and the electric field strength is (K*Q2)/r^2, plugging those values in gives you 
(7.25*10^-11 N) = (1*10^5 N/C)*Q1 ---> Q1 = 7.25*10^-16 C

3 0

3 years ago

Read 2 more answers